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san4es73 [151]
3 years ago
7

Compare 0.32 and 3.2% use <, =, or >

Mathematics
1 answer:
ololo11 [35]3 years ago
6 0

Answer:

.32 > .032

Step-by-step explanation:

3.2%= .032

.32 _ .032

.32 > .032

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Solve the equation.-21=m/3m<br> m=7<br> m=-7<br> m=-63<br> m=63
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6 0
3 years ago
Abraham ha $16 to spend on five pencils. After buying them, he has $6.25 left. How much was each pencil?​
Serhud [2]

Answer:

$ 1.95 per pencil

Step-by-step explanation:

16 - 6.25 = 9.75

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3 0
3 years ago
Given: AB || DE , AD bisects BE.<br> Prove: ABC = DEC using the ASA postulate.
Ket [755]

Answer:

As per ASA postulate, the two triangles are congruent.

Step-by-step explanation:

We are given two triangles:

\triangle ABC and \triangle DEC.

AD bisects BE.

AB || DE.

Let us have a look at two properties.

1. When two lines are parallel and a line intersects both of them, then <em>alternate angles </em>are equal.

i.e. AB || ED and \angle B and \angle E are alternate angles \Rightarrow \angle B = \angle E.

2. When two lines are cutting each other, angles formed at the crossing of two, are known as <em>Vertically opposite angles </em>and they are are <em>equal</em>.

\Rightarrow \angle ACB = \angle DCE

Also, it is given that <em>AD bisects BE</em>.

i.e. EC = CB

1. \angle B = \angle E

2. EC = CB

3. \angle ACB = \angle DCE

So, we can in see that in \triangle ABC and \triangle DEC, two angles are equal and side between them is also equal to each other.

Hence, proved that \triangle ABC \cong \triangle DEC.

8 0
3 years ago
Please help! Thanks! (:
djyliett [7]
Ok this is simple. first, lets look at the 123 angle, so the entire line is 180. subtract 123 from 180 and you have 57. a triangle will always add up to 180 degress aswell. so add 58 and 57 and thats 115. so since a triangle will always add up to 180, subtract 115 from 180 and you have the missing angle:

65!
4 0
3 years ago
Construct a rectangle with sides 6cm and 4cm.​
Bess [88]

Answer:

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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