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Svetllana [295]
3 years ago
8

Calculate the final price. Round all answers to the hundredths place and

Mathematics
1 answer:
Natalija [7]3 years ago
5 0
Paper math is the way
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Zack and Dave each bought some coins from jerry online. Dave bought 5 more coins than Zack bought
Lubov Fominskaja [6]

Answer & Step-by-step explanation:

number of Dave's coins = number of Zack's coins + 5

The question is asking to find the difference in prices paid (thus "<em>more</em>"), completely unrelated to the number of coins Zack bought as these two numbers are independent of one another. The difference in price can be found by simply multiplying the cost of one coin by 5.

3 0
3 years ago
If corresponding angles are on parallel lines, then their measure is the same _____.
weqwewe [10]

Step-by-step explanation:

always .

plz mark my answer as brainlist.hope this will be helpful to you

6 0
3 years ago
Read 2 more answers
Is -7 greater than -4​
antiseptic1488 [7]
No you’re welcome :)
5 0
3 years ago
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If tanA+sinA=m and tanA-sinA=n.prove that m^2-n^2=4√mn
mash [69]

Let a=\tan A and b=\sin A. Then

m^2-n^2=(a+b)^2-(a-b)^2=(a^2+2ab+b^2)-(a^2-2ab+b^2)=4ab

\implies m^2-n^2=4\tan A\sin A

and

mn=(a+b)(a-b)=a^2-b^2

\implies4\sqrt{mn}=4\sqrt{\tan^2A-\sin^2A}

The expression under the square root can be rewritten as

\tan^2A-\sin^2A=\dfrac{\sin^2A}{\cos^2A}-\sin^2A=\sin^2A\left(\dfrac1{\cos^2A}-1\right)=\sin^2A(\sec^2A-1)

Recall that

\sin^2A+\cos^2A=1\implies\tan^2A+1=\sec^2A

so that

\tan^2A-\sin^2A=\sin^2A\tan^2A

and assuming \sin A>0 and \tan A>0, we end up with

4\sqrt{\tan^2A-\sin^2A}=4\tan A\sin A

so that

m^2-n^2=4\sqrt{mn}

as required.

5 0
3 years ago
Simplify 6days to 4weeks to it lowest term in ratio
FromTheMoon [43]
4 weeks = 28 days,
ratio = 6:28,

simplified ratio = 3:14
8 0
3 years ago
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