Question

PLEASE HELP 25 POINTS

Answer 1

Hello from MrBillDoesMath!

Answer:

First term =  S(1) = 1

Common difference = S(n+1) - S(n) = 1 -6n

t(n) value:  can't answer this as I don't know what t(n) refers to,

Discussion:

Let S(n)  = 4n - 3n^2  

First term:

S(1) = 4(1) - 3(1)^2 = 4 - 3 = 1

Common difference:

S(n+1) - S(n) =    ( 4(n+1) - 3 (n+1)^2) - (4n - 3n^2)

                    =    (4n + 4 - 3n^2 -6n -3) - 4n + 3n^2                

                            (now cancel common terms)

                   = -6n +  4 - 3 = -6n + 1

S(n+1) = S(n) -6n +  1

Thank you,

MrB