The answer would be c.127
33-4(3)
33-12
21
The answer is 21
Maybe rate of change? Im not sure.
the correct question is
<span>The length of a rectangle is represented by 4a + 3b, and its width is represented by 3a-2b. Write a polynomial for the perimeter of the rectangle. What is the minimum perimeter of the rectangle if a=12 and b is a non-zero </span>whole number?
we know that
Perimeter of a rectangle=2*[length + width]
length=(4a+3b)
width=3a-2b
so
P=2*[(4a+3b)+(3a-2b)]-----> P=2*[7a+b]-----> P=14a+2b
the answer part a) is
A polynomial for the perimeter of the rectangle is P=14a+2b
Part b)
for a=12
P=14*12+2b---------> P=168+2b
<span>the minimum perimeter of the rectangle is for b=1
</span>so
P=168+2*1-----> P=170 units
the answer part b) is
the minimum perimeter of the rectangle is 170 units
Answer:
x=7
Step-by-step explanation:
HI + IJ = HJ
3x-5 + x-1 = 7x-27
Combine like terms
4x-6 = 7x-27
Subtract 4x from each side
4x-6 -4x= 7x-27-4x
-6 = 3x-27
Add 27 to each side
-6+27 = 3x-27+27
21 = 3x
Divide by 3
21/3 = 3x/3
7 =x