Answer:

Step-by-step explanation:
If x is inversely porportionaly to y, then for some constant k,

Since y is 4 when x = 18, k is equal to 4*18=72, so the equation is:

Answer:
m = 5,520.619
Step-by-step explanation:
The given equation is :
y=5,520.619x-1,091.393 ....(1)
The general form of equation is given by :
y = mx +c ...(2)
Where
m is slope of line
c is y-intercept
Comparing equation (1) and (2), we get :
Slope, m = 5,520.619
Hence, the slope of the given line is 5,520.619.
Answer:
30 miles
Step-by-step explanation:
In this context, "per" means "divided by", so to find miles per gallon, divide miles by gallons:
(56 1/4 mi)/(1 7/8 gal) = 30 mi/gal
The vehicle can travel 30 miles per gallon of gas.
_____
My calculator divides mixed numbers directly, as many graphing calculators do. If you're working this out by hand, you can convert to improper fractions, then multiply the numerator by the inverse of the denominator.
(56 1/4)/(1 7/8) = (225/4)/(15/8)
= (225/4)·(8/15) = (225/15)·(8/4)
= 15·2 = 30
Answer:
P is exactly 3km east from the oil refinery.
Step-by-step explanation:
Let's d be the distance in km from the oil refinery to point P. So the horizontal distance from P to the storage is 3 - d and the vertical distance is 2. Hence the diagonal distance is:

So the cost of laying pipe under water with this distance is

And the cost of laying pipe over land from the refinery to point P is 400000d. Hence the total cost:

We can find the minimum value of this by taking the 1st derivative and set it to 0

We can move the first term over to the right hand side and divide both sides by 400000


From here we can square up both sides






d = 3
So the cost of pipeline is minimum when P is exactly 3km east from the oil refinery.
Answer:
2/29
Step-by-step explanation:
If 9 play none, of the 29 students, 29-9 =20 play at least one. If 14 play basketball, then 20-14 = 6 play only baseball. Since 8 play baseball, there must be 8-6 = 2 who play both baseball and basketball.
Choosing at random, the probability is 2/29 that a student will be chosen who plays both sports.