set A = {2, 4, 6, 8, 10} (only even cards)
set B = {8, 9, 10} (8 or higher)
( A ∩ B ) means the numbers which are common in both sets .
They both have 8 & 10 in common.
So the answer is: P(A ∩ B) = {8,10}
Even if they both spent all of their money, they would still be $0.43 short.
Leon’s $65 and Jennas $50 makes $115. Since they need $115.43, it doesn’t matter how they split the money as they wouldn’t have enough
Hope this helps :)
Answer:
6
Step-by-step explanation:
You must find the least common multiple of their schedules.
The numbers 3 and 2 are their own prime factors, so the least common multiple of 3 and 2 is 6.
Six weekends must pass until they can both have someone over on the same night.
The number line below shows that the first time their sleepovers coincide is Week 6.
180
180- 40=140
140 / 2= 70
Answer:
3/5 or 0.6
Step-by-step explanation:
Here, given the value of tan theta , we want to find the value of sine theta
Mathematically;
tan theta = 0pposite/adjacent
Sine theta = opposite/hypotenuse
Firstly we need the length of the hypotenuse
This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.
Let’s call the hypotenuse h
h^2 = 3^2 + 4^2
h^2 = 9 + 16
h^2 = 25
h = √(25)
h = 5
Now from the tan theta, we know that the opposite is 3
Thus, the value of the sine theta = 3/5 or simply 0.6
