Answer:
Return trip travel time: 7h
Step-by-step explanation:
Let d be the distance.
Index 1 refers to initial trip, index 2 refers to the return trip.
v1=70mi/h
v2=40mi/h
t2=t1+3h, or t1=t2-3h (travel times)
d=v1×t1=v2×t2
v1×(t2-3)=v2×t2
v1 t2 -3 v1=v2 t2
v1 t2 - v2 t2=3 v1
t2(v1-v2)=3v1
t2=3v1/(v1-v2)
Or
t2=3×70/(70-40)=3×70/30=7h
Ok so 8:12 can be 8 to 12, or 8\12
do that help?
Answer:
0.8 hours
Step-by-step explanation:
From the question;
- Speed of Min-jun is 27 miles per hour
- Distance covered is 21 miles
We need to determine the time he takes to cover the distance given;
We need to know that;
Speed = Distance ÷ time
Rearranging the formula;
time = Distance ÷ speed
Thus;
Time = 21 miles ÷ 27 miles per hour
= 7/9 hours
= 0.8 hours
Thus, he took 0.8 hours to cover the distance covered
I think it would be 5005.08 .i hope this has helped you
Answer:
e
Step-by-step explanation:
2.16/3=72c
