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2 years ago

Will mark brainliest

Mathematics

1 answer:

LenaWriter [7]2 years ago

7 0

This dot plot shows a nonlinear association... this is because if you look at the plot you can tell that there isn’t a line going any direction, it’s kinda scattered..so there isn’t any outliers rather it’s a nonlinear plot

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Jen is 3 years older than nancy . Let x represent nancy's age. Let y represent jen's age. Create an equation to show nancy's age

Llana [10]

The equation would be x+3=y
nancy's age + three years= Jen's age

5 0

3 years ago

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Carmen cuts a 60-inch-long wire into pieces that are 3/4 inch long.How many pieces does she have?

miskamm [114]

Since we have to divide 60 by ¾, so get 60/ ¾ =60* 4/3 = 80

7 0

3 years ago

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If 12 cars are needed o get 36 students to the end of the road with their packs, how many cars will be able to carry 9 students

Alina [70]

Answer:

3 cars

Step-by-step explanation:

If 12 cars are needed to carry 36 students,

12cars = 36

the number of cars to carry 9 students will be:

xcars = 9

cross the two equations

36x = 12 X 9

36x = 108

x = 108/36

x= 3

Therefore, 3 cars are needed to carry 9 students

12 cars will carry 36 students

so 1 car will carry, (36/12)students

therefore, 1 car will carry 3 students

So, for 9 students,

9students = 9/3 = 3

7 0

3 years ago

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Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago

Right now, Simran's father is three times as old as Simran. Five years ago, he was four times as

Illusion [34]

Hello,

Let's f the age of the father
s the age of Simran

f=3*s
f-5=4*(s-5)
==>3s-5=4s-20
==>s=15
f=3*15=45

3 0

3 years ago

Read 2 more answers