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Anna11 [10]
3 years ago
5

A theorem that allows us to use the normal probability distribution to approximate the sampling distribution of sample means and

sample proportions whenever the sample size is large is known as _______________.
Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0
The answer is the central limit theorem
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A spring stretches out by 8cm when a 0.2 kg weight is placed on it. How much does the spring stretch by when a 0.5 kg weight is
Ierofanga [76]

m₁ = mass hanged initially = 0.2 kg

x₁ = initial stretch in the spring = 8 cm = 0.08 m

k = spring constant of the spring

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₁ = m₁ g

k (0.08) = (0.2) (9.8)

k = 24.5 N/m


m₂ = mass hanged later = 0.5 kg

x₂ = final stretch in the spring = ?

k = spring constant of the spring = 24.5 N/m

the weight of the mass hanged is balanced by the spring force by the spring hence

Spring force = weight of mass hanged

k x₂ = m₂ g

(24.5) x₂  = (0.5) (9.8)

x₂  = 0.2 m = 20 cm



5 0
3 years ago
I NEED HELP!! with this homework please. For B,C,and D, if you know the answer please tell me I’m kinda confused.
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

       Location    Reflect over x              Reflect over y

B      -0.75 ,1         -0.75 ,-1                           +0.75 ,1

C     1.75 ,-1          1.75,1                                 -1.75,+1

D      -2,-2           -2,+2                                  +2 ,-2

8 0
3 years ago
52. In exploring possible sites for a convenience store in a large neighborhood, the retail chain wants to know the proportion o
kvasek [131]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04  

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. We know that we require a 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

We want a margin of error of ME =\pm 0.1 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

Since we don't have prior info for the population proportion we can use as estimator the value of 0.5. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.1}{1.96})^2}=96.04  

Then the minimum sample size in order to satisfy the condition of 0.1 for the margin of error is 97 and since the sample used is n =100 we can conclude that is sufficient and the best answer would be:

D. Yes.

4 0
3 years ago
Find the area<br><br> A. 50in<br> B. 60in<br> C. 50in2<br> D. 60in2
ludmilkaskok [199]

Answer:

The answer is 60in^2

Step-by-step explanation:

5 0
3 years ago
The temperature was 54 at 7:00 a.m. At 3:00 p.m. on the same day, the temperature was 82. What is the rate of change in temperat
vampirchik [111]

Answer:

The rate of change was 3.5 degrees / h.

Step-by-step explanation:

In order to calculate the rate of change we need to divide the variation of temperature by the variation of time. Since the time is given to us in a 12 h format (am/pm), we first need to convert it to 24 h. To do that we sum the time that is "pm" by 12, we have:

time2 = 3 + 12 = 15

Therefore the rate of change in temperature is:

rate = variation of temp / variation of time

rate = (temp final - temp init) / (time final - time init)

rate = (82 - 54) / (15 - 7) = 28 / 8 = 3.5 degrees / h

The rate of change was 3.5 degrees / h.

4 0
4 years ago
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