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Rama09 [41]
3 years ago
15

find a number such that if you add 8 and divide the result by 4 you will get the same answer as if you subtracted 3 from the ori

ginal number and divided by 2
Mathematics
1 answer:
blagie [28]3 years ago
8 0

Answer:

14

Step-by-step explanation:

First condition

Let the number be x

\dfrac{x+ 8}{4} = \dfrac{x - 3}{2}       Cross multiply

2(x + 8) = 4*(x - 3)                             Remove the brackets

2x + 16 = 4x - 12                               Add 12 to both sides

2x + 16 + 12 = 4x - 12 + 12                Simplify

2x + 28 = 4x                                     Subtract 2x from both sides

2x - 2x + 28 = 4x - 2x                      Simplify

28 = 2x                                             Divide both sides by 2

28/2 = 2x/2                

x = 14

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Answer:

The cost of each cotton candy bag is $4.

Step-by-step explanation:

Consider the provided information.

Let, the vendor has x dollar at the starting of each day.

Let, the cost of each cotton candy bag is y.

Now when she sells a total of 12 bags, she has $128.

x+12y=128  .....(1)

After she sells a total of 20 bags, she has $160.

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A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
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There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

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P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

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P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

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3 years ago
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