Plug in y=3x+2 into the y in the second equation.

x + 2(3x+2) = 11
x + 6x + 4 = 11
7x + 4 = 11
7x = 7
x = 1

then, plug the x value into x in the first equation.

y = 3(1) + 2
y = 3 +2
y = 5

3 0

3 years ago

How do I factorise 2t^2 + 5t +2

alekssr [168]

$2t^2+5t+2\\\\a=2;\ b=5;\ c=2\\\\\Delta=b^2-4ac;\ if\ \Delta > 0\ then\ t_1=\frac{-b-\sqrt\Delta}{2a}\ and\ t_2=\frac{-b+\sqrt\Delta}{2a}\\\\\Delta=5^2-4\cdot2\cdot2=25-16=9;\ \sqrt\Delta=\sqrt9=3\\\\t_1=\frac{-5-3}{2\cdot2}=\frac{-8}{4}=-2;\ t_2=\frac{-5+3}{2\cdot2}=\frac{-2}{4}=-\frac{1}{2}\\\\2t^2+5t+2=2(x+2)(x+\frac{1}{2})$

5 0

3 years ago

Factor: 6x^2 + 4t - 2

Eddi Din [679]

Answer:

2(3x2+2t−1)

Step-by-step explanation:

6x2+4t−2

=2(3x2+2t−1)

4 0

3 years ago