Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
a. Definition of segment Bisector
b. Line segment KM
c. Given
d. Definition of segment bisector
e. Reflexive property of congruence
f. SAS
g. CPCTC (Corresponding parts of congruent triangles are congruent)
Answer
Sol: The correct answer is b. three planes that contain point B are ABD, AEF and DHF.
F(x)=(3x-2)^0.5
C.x is greater than or equal to two thirds
Answer:
In inches it would be 370.36
Step-by-step explanation: