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Serjik [45]
3 years ago
5

Double my tens digit to get my ones digit. Double me and I less than 50

Mathematics
2 answers:
frez [133]3 years ago
8 0
It could be anything with a tens digit half of ones digit
Happy to Help!
pickupchik [31]3 years ago
6 0
One example of this number is 24, or maybe 12, just follow the rules and you'll have a lot of answers.
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A)line a and line b<br> B)line b and line c<br> C)line b and line d<br> D) line c and line d
jarptica [38.1K]

A)line a and line b is your answer.

6 0
3 years ago
Use prime factorization to reduce 36/180
Nataly [62]
The fraction 36/180 can be recuced to 1/5 because 36 divided by 36 is 1 and 180 divided by 36 is 5 hope it helped :)
3 0
2 years ago
If (w+13)^2=(3w+7)(2w+4), find w^2. Express your answer as a decimal.
faltersainse [42]
Answer: w² equals to 28.2
4 0
3 years ago
What is the equation of the line parallel to x = 7, passing through the point (-4, 1)? A. X = -4 B. X = 1 C. Y = -4 D. Y = 1
77julia77 [94]

Answer:

x=-4

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
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