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Shalnov [3]
3 years ago
12

Chelsea did yard work for 7 hours last weekend. Her parents paid her $40. How much did she get paid per hour?

Mathematics
2 answers:
Igoryamba3 years ago
8 0

Answer:

$5.71

Step-by-step explanation:

40 divided by 7 equals 5.71428571, which should be rounded to 5.71.

Nezavi [6.7K]3 years ago
5 0
Since it’s only 7 hours she’s getting paid around $5 an hour
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Consumer Reports will have an article comparing refrigerators in the next issue. Some of the characteristics to be included in t
kap26 [50]

Answer:

brand name and model - - > CATEGORICAL

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Step-by-step explanation:

Given the following refrigerator characteristics :

brand name and model - - > CATEGORICAL

whether it has a top freezer, bottom freezer, or side-by-side LAYOUT - - > CATEGORICAL

the estimated energy consumption per year (kilowatts); - - - > QUANTITATIVE

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To start with ; Categorical and quantitative variables differ most notably in the fact that, quantitative variables deals with numbers, measurements or calculated mathematical values of certain attribute in a measured species or sample. Categorical variable on the other hand mostly deals with making distinctions in properties of a sample by grouping the varibale into the different available categories based on their attributes.

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3 years ago
Pls help with this question. No links.
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Answer:

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Answer:

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Here we have:

f(x) = 4*cos(x)

a = 7*pi

then, let's calculate each part:

f(a) = 4*cos(7*pi) = -4

df/dx = -4*sin(x)

(df/dx)(a) = -4*sin(7*pi) = 0

(d^2f)/(dx^2) = -4*cos(x)

(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4

Here we already can see two things:

the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.

so we only will work with the even powers of the series:

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6 0
3 years ago
Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.
Leya [2.2K]

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\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}

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6 0
3 years ago
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