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Leto [7]
3 years ago
5

Yana is using an indirect method to prove that segment DE is not parallel to segment BC in the triangle ABC shown below: A trian

gle ABC is shown. D is a point on side AB and E is a point on side AC. Points D and E are joined using a straight line. The length of AD is equal to 4, the length of DB is equal to 5, the length of AE is equal to 6 and the length of EC is equal to 7. She starts with the assumption that segment DE is parallel to segment BC. Which inequality will she use to contradict the assumption? 4:9 ≠ 6:13 4:9 ≠ 6:7 4:13 ≠ 6:9 4:5 ≠ 6:13

Mathematics
2 answers:
kolezko [41]3 years ago
7 0

Please see attached file for the triangle’s figure:

 

Going with the image attached, if DE is parallel to BC<span>
then
<span>4: (4 + 5) = 6 : (6 + 7).

Therefore, the inequality that she will use to contradict the assumption</span> is 4:9 ≠ 6:13</span>.

To add, a relation that holds between two values when they are different in mathematics is called an inequality. A is not equal to b also means the notation a ≠ b.

<span><span>

</span>Inequalities are governed by the following properties<span>:

Transitivity</span></span>
 Converse
 Addition and subtraction
 Multiplication and division
 Additive inverse
 Multiplicative inverse
<span>Applying a function to both sides</span>

OleMash [197]3 years ago
6 0

Answer:

4:9 ≠ 6:13.

Step-by-step explanation:

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4 0
3 years ago
Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the
VikaD [51]

In general, the exponential growth function is given by the formula below

f(x)=a(1+r)^x

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}

And 1976 is n=16

\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}

Solve the two equations simultaneously, as shown below

\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}

Solving for a,

\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}

a) Thus, the equation is

\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n

b) 1960 is n=0; thus,

f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots

The answer to part b) is $1.113043... per hour

c)1996 is n=36

\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}

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(−8p ^3 +9p ^2q −5pq ^2) + (8p ^3 − pq + 5q ^2)
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Answer:

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3 years ago
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likoan [24]

Answer:

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y + 3 = -4/3 x + -12

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irina [24]
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7 0
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