Question

Find the missing side of a right triangle with leg length 5 yards and hypotenuse 13 yards.

Answer 1

$answer =12 \: yards \\ solution \\ hypotenuse(h) = 13 \: yards \\ perpendicular(p) = 5 \: yards \\ base(b) = ?\\ using \: pythagorus \: theorem \\ {h}^{2} = {p}^{2} + {b}^{2} \\ {b}^{2} = {h}^{2} - {p}^{2} \\ {b}^{2} = {13}^{2} - {5}^{2} \\ {b}^{2} = 169 - 25 \\ {b}^{2} = 144 \\ b = \sqrt{144 } \\ b = \sqrt{ {12}^{2} } \\ b = 12 \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment$

Answer 2

Answer:

Step-by-step explanation:

Use Pythagorean theorem

let the missing side be x

5² +x² = 13²

25 + x² = 169

x² = 169 - 25

x² = 144

x =√144

x = 12 yards