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lisabon 2012 [21]
3 years ago
13

Graph the line passing through the point (2, - 2) with the slope m = 4/3

Mathematics
1 answer:
SVEN [57.7K]3 years ago
3 0
This should be it, hope it helps :)

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Following world war 1 the allies
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Made the treaty of versai witch put restrictions on Germany and made the pay for the destruction they caused during the war putting them in a spot were they had no money 
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What is the value of 5x+ 3 when X= 4?<br> 9<br> 12<br> 23<br> 60
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The answer is 23 because you would substitute in the 4 for the X and multiply 5 times 4 = 20 then add 20 plus 3 and you get 23
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the mean of normally distributed test scores is 80 and the standard division is 5. If there are 186 test scores in the data samp
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Answer:

63

Step-by-step explanation:

score 75 is one standard dev below the mean ====>to the mean  encompasses approx 34% of scores

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2 years ago
Assume that two chords in a given circle are the same distance from the
Alenkinab [10]

Step-by-step explanation:

If the two chords are congruent, then they must be equidistant from the centre of the circle.

Answer: <u><em>D) They must be perpendicular</em></u>

A is rejected because the chord might not pass through the center of the circle.

B is rejected because the chords are not obligated to be parallel.

C is rejected because it is not compulsory for the chords to be perpendicular.

4 0
3 years ago
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Given that rectangle LMNO with coordinates L(0,0), M(3,0), N(3,7), O(0,7), P is the midpoint of LM⎯⎯⎯, and Q is the midpoint of
Elina [12.6K]

The midpoint of a line divides the line into equal segments.

The option that proves PQ = LO is (a)

The given parameters are:

\mathbf{L = (0,0)}

\mathbf{M = (3,0)}

\mathbf{N = (3,7)}

\mathbf{O = (0,7)}

P is the midpoint of LM.

So, we have:

\mathbf{P = \frac{LM}{2}}

\mathbf{P = (\frac{(0 +3}{2},\frac{0+0}{2})}

\mathbf{P = (\frac{3}{2},0)}

Q is the midpoint of NO.

So, we have:

\mathbf{Q = \frac{NO}{2}}

\mathbf{Q = (\frac{(3 +0}{2},\frac{7+7}{2})}

\mathbf{Q = (\frac{3}{2},7)}

Distance PQ is calculated as follows:

\mathbf{d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}

This gives:

\mathbf{PQ = \sqrt{(3/2 - 3/2)^2 + (0 - 7)^2}}

\mathbf{PQ = \sqrt{ 7^2}}

\mathbf{PQ = 7}

Distance LO is calculated as follows:

\mathbf{LO = \sqrt{(0 - 0)^2 + (0 - 7)^2}}

\mathbf{LO = \sqrt{ 7^2}}

\mathbf{LO=7}

So, we have:

\mathbf{PQ = 7}

\mathbf{LO=7}

Thus:

\mathbf{PQ = LO}

Hence, the correct option is (a)

Read more about distance and midpoints at:

brainly.com/question/11231122

8 0
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