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3 years ago

Which electron transition produces light of the highest frequency in the hydrogen atom?

Physics

1 answer:

allsm [11]3 years ago

7 0

Answer:

To identify the electron transition that has the highest frequency in the hydrogen atom.Answer: The frequency of light produced by electron transition is highest among the given electron transition, therefore, the option (a) is correct.Explanation:The energy of emitted light by the electron transition is given as: is the energy of the initial level. is the energy of the final level.The energy difference for the electron transition is highest among given electronic transition.The energy of the light is given as:Here, is the plank’s constant. is the frequency of the light.The energy of the light is directly proportional to the frequency of the light.Therefore the frequency of light by the electron transition is highest among given electronic transition.

Explanation:

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Can some answer 7 a and b please

pav-90 [236]

Answer:

a.After $15$ second Mr Comer's speed $=$ $1.7 m/s$

b.Distance travelled by Mr.Comer in $15$ seconds $=$ $18.75\ m$

Explanation:

a. Lets recall our first equation of motion $V_{f} =V_{i} + at$

Now we know that $V_{i} = 0.8m/s$ , $a = 0.06\ m/s^2$ and

$t = 15 \ sec$

Plugging the values we have.

$V_{f} =V_{i} + at$

$V_{f} =0.8 + 0.06 \times 15$

$V_{f} =0.8+ 0.9$

$V_{f} =1.7 m/s$

Then Mr.Comer's speed after $15$ sec $=$ $1.7ms^-1$

Lets find the distance and recall our third equation of motion.

$V_{f} ^2-V{i}^2 = 2as$

So $s =$ distance covered.

Dividing both sides with 2a we have.

$\frac{V_{f} ^2-V{i}^2}{2a} = 2as$

Plugging the values.

$\frac{(1.7)^2-(0.8)^2}{2\times0.06} = 2as$

$s= 18.75\ m$

So Mr.Comer will travel a distance of $s= 18.75\ m$ .

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3 years ago

The father sake to his daughter am happy with you change into reported speech

lisov135 [29]

Answer:

I am happy with you the father said to his daughter

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3 years ago

School homework about multiplying fractions <br><br>worth 30 brainly points

RoseWind [281]

Answer:

Explanation:

1. $\frac{1}{3}$ x $\frac{6}{7}$ = $\frac{6}{21}$

= $\frac{2}{7}$

b. $\frac{6}{8}$ + $\frac{4}{9}$ = $\frac{24}{72}$

= $\frac{1}{3}$

c. $\frac{10}{15}$ x $\frac{3}{4}$ = $\frac{30}{60}$

= $\frac{1}{2}$

d. $\frac{7}{10}$ of $\frac{5}{10}$ = $\frac{7}{10}$ x $\frac{5}{10}$

= $\frac{35}{100}$

= $\frac{7}{20}$

e. $\frac{3}{8}$ of $\frac{4}{6}$ = $\frac{3}{8}$ x $\frac{4}{6}$

= $\frac{12}{48}$

= $\frac{1}{4}$

f. $\frac{7}{12}$ of $\frac{9}{14}$ = $\frac{7}{12}$ x $\frac{9}{14}$

= $\frac{63}{168}$

= $\frac{3}{8}$

2. $\frac{22}{6}$ x $\frac{3}{11}$ = $\frac{66}{66}$

= 1

b. $\frac{15}{6}$ x $\frac{4}{5}$ = $\frac{60}{30}$

= 2

c. $\frac{25}{8}$ x $\frac{4}{10}$ = $\frac{100}{80}$

= $\frac{5}{4}$

d. $\frac{33}{12}$ x $\frac{4}{15}$ = $\frac{132}{180}$

= $\frac{11}{15}$

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3 years ago

This spectrometer reading shows some red, blue, and purple. Our atom is most likely ______________________.

Kisachek [45]

<span>This spectrometer reading shows some red, blue, and purple. Our atom is most likely Hydrogen source.

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This spectrometer reading shows some red, yellow, and blue. Our atom is most likely Helium source.

This spectrometer reading shows some yellow, blue, and purple. Our atom is most likely Mercury source</span>

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The container is filled to yh 350 ml mark water is observation or inference?

Lorico [155]

This is an observation.

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3 years ago