Answer:
In fact, carving letters into a tree probably won't hurt it. ... In general, the tree will compartmentalize the wound and it will heal over. The initials that remain visible are essentially scar tissue, permanent scar tissue.
Explanation:
Unfortunately, when carving into the trunk of a tree the blade of a knife often penetrates the outer bark and cuts into the inner bark. ... In cases that the phloem is damaged all the way around the trunk (in a ring for example), the tree will slowly and eventually starve to death.
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luke_raines19
Answer:
because they are the rocks that line the surface of our planet
Explanation:
We see sedimentary rocks more than other rock types because they are the rocks that line the surface of our planet.
Sedimentary rocks typically form the earth cover due to the way they are formed.
- These rocks are produced by the weathering, transportation and deposition of sediments within a basin.
- In this basin, the sediment is lithified and converted to sedimentary rocks.
- These processes are driven by the external heat engine
- Therefore, it is confined to the surface.
- Igneous and metamorphic rock's processes are confined to the subsurface.
Answer:
Time period of the motion will remain the same while the amplitude of the motion will change
Explanation:
As we know that time period of oscillation of spring block system is given as
now we know that
M = mass of the object
k = spring constant
So here we know that the time period is independent of the gravity
while the maximum displacement of the spring from its mean position will depends on the gravity as
so we can say that
Time period of the motion will remain the same while the amplitude of the motion will change
Answer:
Option C is correct
Explanation:
A supersaturated solution is one that has more solute dissolved than the solution should hold at that temperature.
Examples include carbonated water, sugar syrup, honey.
A solution of a chemical compound can be dissolved in heated water to prepare a supersaturated solution. A solution becomes supersaturated as its temperature is changed.
Answer:
1.15*10^-5 kg/m^3
Explanation:
Given data
mass= 1kg
hieght= 40 mm
diameter= 52.5mm
radius= 53.5/2= 26.25mm
The volume of the cylinder
V=πr^2h
V=3.142*26.25^2*40
V=3.142*689.0625*40
V=86601.375 mm^3
Density= mass/volume
Density= 1/86601.375
Density=0.00001154716
Density= 1.15*10^-5 kg/m^3
Hence the density is 1.15*10^-5 kg/m^3
