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jeka57 [31]
3 years ago
15

A car travels from point a to point b, moving in the same direction but with a non-constant speed. the first half of the distanc

e, the car travels with a speed v_1v ​1 ​​ . the remaining part of the way, the car travels half the time with a speed v_2v ​2 ​​ and half the time with a speed v_3v ​3 ​​ . what is the average speed over the entire journey
Physics
2 answers:
Naddik [55]3 years ago
6 0
You have to devide and add evreythuy butthe answer is 464
Ira Lisetskai [31]3 years ago
5 0

Answer:

\frac{4v_1v_2v_3}{2v_2v_3+v_1v_2+v_1v_2}

Explanation:

The average speed is given by:

v_{avg}= \frac{\text{total distance}}{\text{total time taken}}

let the total distance be d

time taken in first part of the journey= t₁

t_1 = \frac{d/2}{v_1}

time taken in second part of the journey= t₂

t_2 = \frac{d/4}{v_2}

time taken in third part of the journey= t₃

t_3 = \frac{d/4}{v_3}

v_{avg}= \frac{d}{t_1+t_2+t_3}=\frac{d}{\frac{d/2}{v_1}+\frac{d/4}{v_2}+\frac{d/4}{v_3}}

v_{avg}=\frac{4v_1v_2v_3}{2v_2v_3+v_1v_2+v_1v_2}

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Six new refrigerator prototypes are tested in the laboratory. For each refrigerator, the electrical power P needed for it to ope
Mandarinka [93]

Answer:

performance coefficient from largest to the smallest

P= 500 W, Qc,max/deltaT= 2000 J/s

P= 250 W, Qc,max/deltaT= 1000 J/s

P= 750 W, Qc,max/deltaT= 1500 J/s

) P= 400 W, Qc,max/deltaT= 1200 J/s

P= 500 W, Qc,max/deltaT= 1500 J/s

P= 1000 W, Qc,max/deltaT= 3000 J/s.

the rate at which they raise the temperature of the room.

2.1.P= 1000 W, Qc,max/deltaT= 3000 J/s

P= 500 W, Qc,max/deltaT= 2000 J/s

P= 750 W, Qc,max/deltaT= 1500 J/s

P= 500 W, Qc,max/deltaT= 1500 J/s

P= 400 W, Qc,max/deltaT= 1200 J/s

P= 250 W, Qc,max/deltaT= 1000 J/s

Explanation:

A refrigerator is a device that uses work to remove heat energy from a cold reservoir and deposit it into a hot reservoir. .A good refrigerator (with a large performance coefficient) will remove a large amount of heat energy from the cold reservoir for a small amount of work input

The performance coefficient  of a refrigerator is defined as the ratio of the heat energy removed from the cold reservoir  to the work  input to the refrigerator:

k=QC/W

power is defined as work per unit time

1.k=1500/750=2

2. 1200/400=3

3.2000/500=4

4.1000/250=4

5.1500/500=3

6.3000/1000=3

performance coefficient from largest to the smallest

P= 500 W, Qc,max/deltaT= 2000 J/s

P= 250 W, Qc,max/deltaT= 1000 J/s

P= 750 W, Qc,max/deltaT= 1500 J/s

) P= 400 W, Qc,max/deltaT= 1200 J/s

P= 500 W, Qc,max/deltaT= 1500 J/s

P= 1000 W, Qc,max/deltaT= 3000 J/s

2, Rate at which they raise the temperature of the room.

rate at which temperature rises in the inner chamber of the refrigerator is proportional to the rate of energy used to dispel heat from the refrigerator

1.P= 1000 W, Qc,max/deltaT= 3000 J/s

P= 500 W, Qc,max/deltaT= 2000 J/s

P= 750 W, Qc,max/deltaT= 1500 J/s

P= 500 W, Qc,max/deltaT= 1500 J/s

P= 400 W, Qc,max/deltaT= 1200 J/s

P= 250 W, Qc,max/deltaT= 1000 J/s

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3 years ago
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