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3 years ago

A force F~ = Fx ˆı + Fy ˆ acts on a particle that

Physics

1 answer:

Nadusha1986 [10]3 years ago

8 0

Answer: Work done is 18J

Explanation:

Force F = (Fx, Fy) and Displacement S = (Sx,Sy)

Fx=7N

Fy=-1N

Sx=3m

Sy=3m

F=(7,-1)N and S=(3,3)m

Work done is calculated by taking dot product of force and displacement vector

W=F·S

W=7×3 + (-1)×3

W=21+(-3)=18J

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3 years ago

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Answer:

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Explanation:

The weight of an object is on the surface of earth is given by the following formula:

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3 years ago

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Hello!

Let's begin by doing a summation of torques, placing the pivot point at the attachment point of the rod to the wall.

$\Sigma \tau = 0$

We have two torques acting on the rod:
- Force of gravity at the center of mass (d = 0.700 m)

- VERTICAL component of the tension at a distance of 'L' (L = 2.200 m)

Both of these act in opposite directions. Let's use the equation for torque:
$\tau = r \times F$

Doing the summation using their respective lever arms:

$0 = L Tsin\theta - dF_g$

$dF_g = LTsin\theta$

Our unknown is 'theta' - the angle the string forms with the rod. Let's use right triangle trig to solve:

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$T = \frac{dMg}{Lsin\theta}$

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