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Ad libitum [116K]
3 years ago
12

A force F~ = Fx ˆı + Fy ˆ acts on a particle that

Physics
1 answer:
Nadusha1986 [10]3 years ago
8 0

Answer: Work done is 18J

Explanation:

Force F = (Fx, Fy) and Displacement S = (Sx,Sy)

Fx=7N

Fy=-1N

Sx=3m

Sy=3m

F=(7,-1)N and S=(3,3)m

Work done is calculated by taking dot product of force and displacement vector

W=F·S

W=7×3 + (-1)×3

W=21+(-3)=18J

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I gotchu, the answer’s elastic potential energy.
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I have an algerbra 2 question.
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In order to find out if the exponential function represents a growth or a decay, let's look at the number that is base to the exponent x.

If the number is greater than 1, so the function represents a growth, and if the number is less than 1, the function represents a decay.

Since the number is 1.075, the function represents a growth.

To find the % increase, first let's convert the number to percentage, and then subtract 100%:

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1 year ago
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3 years ago
A bat at rest sends out ultrasonic sound waves at 46.2 kHz and receives them returned from an object moving directly away from i
murzikaleks [220]

Answer:

f" = 40779.61 Hz

Explanation:

From the question, we see that the bat is the source of the sound wave and is initially at rest and the object is in motion as the observer, thus;

from the Doppler effect equation, we can calculate the initial observed frequency as:

f' = f(1 - (v_o/v))

We are given;

f = 46.2 kHz = 46200 Hz

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Thus;

f' = 46200(1 - (21/343))

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In the second stage, we see that the bat is now a stationary observer while the object is now the moving source;

Thus, from doppler effect again but this time with the source going away from the obsever, the new observed frequency is;

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3 years ago
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