In a capture/recapture program, 30% of the animals recaptured have tags. Suppose 70 animals were originally captured, tagged and
1 answer:
Answer:
Approximately , there are 233 animals in the forest.
Step-by-step explanation:
There was a capture program of animals to get a count of the animals in that region.There were two rounds for that program. In the first round 70 animals were captured and all of them were tagged . In the second round , there were more animals caught but only 30% of those newly caught animals had tags.
Here we have to assume that no animal loses tag.
Let the total population be x .
Then 30% of the total population is 70.
Writing equation ,
x =233 animals
Approximately , there are 233 animals in the forest.
You might be interested in
Using the condition given to build an inequality, it is found that the maximum number of junior high school student he can still recruit is of 17.
<h3>Inequality:</h3>Considering s the number of senior students and j the number of junior students, and that he cannot recruit more than 50 people, the inequality that models the number of students he can still recruit is:
In this problem:
- Already recruited 28 senior high students, hence
.
- Already recruited 5 junior high students, want to recruit more, hence
.
Then:
The maximum number of junior high school student he can still recruit is of 17.
You can learn more about inequalities at brainly.com/question/25953350
We must recall that a horizontal asymptote is the value/s of y that the given function approaches to but never reaches. To find this in a rational function, we compare the expressions with highest degree in the numerator and denominator. There are three possible outcome when this happens.
1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.
2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.
3. if they have the same highest degree, then we just get the quotient of their coefficient.
Now, going back to our function, we have
From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.
Answer: y = 0
1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.
2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.
3. if they have the same highest degree, then we just get the quotient of their coefficient.
Now, going back to our function, we have
From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.
Answer: y = 0