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3 years ago

Are the following expressions equivalent? Why or why not? 6(2x + 4) and 12x + 24

Mathematics

1 answer:

MrMuchimi3 years ago

8 0

Answer: Yes

Step-by-step explanation:

When using the distributive property, 6(2x + 4) becomes 12x + 24

6 * 2x = 12x and 6 * 4 = 24

12x + 24 = 12x + 24

Therefore, the expressions are equivalent.

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What is the value of x in the figure at the right

alina1380 [7]

We can know from the pic
2x+38=90
so, x=26

6 0

3 years ago

If I had to transfer 3 litres of water from one container to another with only a mug which can hold 1/8 of a litre each time, ho

miv72 [106K]

24 times as it takes 8 times to fill 1 Litre so 8x3 = 24

6 0

4 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago

Select the correct answer.

Afina-wow [57]

Answer:

$d)\ \frac{81}{m^{7}}$

Step-by-step explanation:

$(3m^-4)^3(3m^5)$

First, simplify $(3m^{-4})^3$ :

$(3m^{-4})^3\\\\3^3*m^{-4*3}\\\\27m^{-12}$

$27m^{-12}*3m^5\\\\27*3 *m^{-12+5}\\\\81m^{-7}\\\\81*\frac{1}{m^{7}} \\\\\frac{81}{m^{7}}$

Hope this helps!

5 0

2 years ago

PLEASE HELP ME :(( i tried 12 as the answer and it’s wrong

AnnZ [28]

I think its 1/6

I'm not sure tho

u take the bottom and subtract it by the top then multiply

6 0

3 years ago

Read 2 more answers