Answer:
1) Known information:
- The perimeter.
- ![width=lenght-3ft](https://tex.z-dn.net/?f=width%3Dlenght-3ft)
- The formula of the perimeter of the rectangle:
![P=2l+2w](https://tex.z-dn.net/?f=P%3D2l%2B2w)
Unknown information:
- The value of the widht.
- The value of the length.
2) Equation:
![530=2l+2w\\530=2l+2(l-3)](https://tex.z-dn.net/?f=530%3D2l%2B2w%5C%5C530%3D2l%2B2%28l-3%29)
3) ![l=134\\w=131](https://tex.z-dn.net/?f=l%3D134%5C%5Cw%3D131)
Step-by-step explanation:
1. The problem gives you the perimeter, the formula of the perimeter of a rectangle and says that the width of a rectangle is 3 feet shorter than its length (
), but does not give the value of the widht and the value of the lenght.
2. Based on the information given, you can write the following equation:
![530=2l+2w](https://tex.z-dn.net/?f=530%3D2l%2B2w)
Where
is the lenght and
is the width.
Substitute
into the equation above, then you have:
![530=2l+2(l-3)](https://tex.z-dn.net/?f=530%3D2l%2B2%28l-3%29)
3. Solve for the lenght:
![530=2l+2(l-3)\\530=2l+2l-6\\536=4l\\l=134](https://tex.z-dn.net/?f=530%3D2l%2B2%28l-3%29%5C%5C530%3D2l%2B2l-6%5C%5C536%3D4l%5C%5Cl%3D134)
4. Know you can calculate the width:
5. Therefore, the length is 134 feet and the widht is 131 feet.