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2 years ago

Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

user100 [1]2 years ago

5 0

Flip a coin twenty five times, the purpose of this is to show that theoretical and experimental do not always overlap.

Theoretically, it should be a fifty-fifty chance.

In the experiment because you do it a odd amount of times, 25, each flip will be worth a four percent chance.

You would not be able to make a fifty fifty chance with that amount of flips.

Also here:

1.) 13 Heads, 12 tails

2.) 48% chance for the coin to land on tails, 52% chance for the coin to land on heads.

3.) The theoretical probability of a coin landing on heads is 50% of the time that the coin is flipped. This is because there are two possibilities with an equal likelihood of happening

4) The theoretical probability and experimental probability are different as theoretically there would be an equal likelihood or probability and in the experiement, there was a higher probability for the coin to land on heads.

vladimir1956 [14]2 years ago

5 0

Flip a coin twenty five times, the purpose of this is to show that theoretical and experimental do not always overlap.

Theoretically, it should be a fifty-fifty chance.

In the experiment because you do it a odd amount of times, 25, each flip will be worth a four percent chance.

You would not be able to make a fifty fifty chance with that amount of flips.

Also here:

1.) 13 Heads, 12 tails

2.) 48% chance for the coin to land on tails, 52% chance for the coin to land on heads.

3.) The theoretical probability of a coin landing on heads is 50% of the time that the coin is flipped. This is because there are two possibilities with an equal likelihood of happening

4) The theoretical probability and experimental probability are different as theoretically there would be an equal likelihood or probability and in the experiement, there was a higher probability for the coin to land on heads.

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e-lub [12.9K]

Y-intercept = -5
slope = 5/2

Answer:
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3 0

2 years ago

Read 2 more answers

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

#SPJ1

5 0

1 year ago

Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma

Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = $x$

Using unitary method to find weight of $x$ horses.

If 1 horse weights = 1,200 lb

Then $x$ horses will weight in lbs = $1,200\times x = 1,200x$

Total weight of horses and trailer in lbs = $1200x+2700$

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

$1200x+2700\leq5000$

Subtracting both sides by 2700.

$1200x+2700-2700\leq5000-2700$

$1200x\leq2300$

Dividing both sides by 1200.

$\frac{1200x}{1200}\leq\frac{2300}{1200}$

$x\leq1.91$

From the inequality solution for $x$ , we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0

3 years ago

To get your car repaired at a certain dealership in Woodstock, the rate charged is $90 per hour worked on your car, plus a $50 d

kakasveta [241]

C- charge
H- hours
D- diagnostic fee

C= #H(90)+ D

C= 4.6(90)+50
=414+50
=$464

C-$800
H-?
D-50

C= #H(90)+50

800=H(90)+50

H(90)=800-50

H(90)=750

H(90)/90=750/90

H=750/90

H= 8.33333333

4 0

2 years ago

Mrs perry shares out 28 biscuits between Gemma and Zak in the ratio 1:6

dsp73

One of them will be given 4 biscuits and the other will be given 24.

5 0

3 years ago