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Naddika [18.5K]
2 years ago
12

What is the product when you multiply the equation below using the standard algorithm.

Mathematics
1 answer:
alex41 [277]2 years ago
8 0
The answer is 33417 423x79 =33417
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A white-tailed deer can sprint at speeds up to 30miles per hour . American bison can run at speeds up to 3,520feet per minute. W
Rus_ich [418]

Answer:

The Bison is faster by 10 mph.

In 1 minute, the bison runs 3, 520 feet .

In 60 minutes, the bison would run  3520*60 feet  = 211, 200 feet per hour.

These are equivalent to 40 miles per hour since 1 mile is equivalent to 5, 280 feet. Hope this helps! ^-^

6 0
3 years ago
Will give brainiest if correct<br><br> A. 69.1<br> B. 20.9<br> C. 22.4<br> D. 67.6
Free_Kalibri [48]
Using sin law;

sin A/ a = sinB/ b

where A = C or 90 degrees; a = 21
B = ? , b = 8

solving for b;
sin(90) / 21 = sin(B) / 8 ; B = 22.39 degrees

Total angle of triangle = 180

180 - 90 - 22.39 = x
x = 67.607 degrees
8 0
3 years ago
Read 2 more answers
Can someone please help me with this one question
erastova [34]

the problem with this study is the fact that they used precise numbers

hope i helped:)

7 0
3 years ago
18 feet long and 12 feet wide. What is the area of the floor in square yards?
forsale [732]
Area of a rectangle =length*width

length=18ft=18/3=6yds
width=12ft=12/3=4yds

answer: A=6*4= 24 yds^{2}
3 0
3 years ago
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Exercise 3 Iron Man is checking out a new suit that fires lasers more accurately. If he is aiming for a bullseye, his original s
Novosadov [1.4K]

Answer: (a). insufficient evidence.

(b). sufficient evidence

(c). insufficient evidence

Step-by-step explanation:

we will analyse this carefully to help us understand it better.

we have the standard deviation for the original suit = 2mm

standard deviation for new suit = 1.6mm

given n = 1.6

from the question we know that  the  suit with less standard deviation is better than the other suit

considering a null hypothesis;

H₀ : б ≥ 2, (here the new suit is not better than the original alternative hypothesis).

Also Hi : б < 2 (we have here that the new suit is better than the original )

using the Chi-Square distribution with n-1 degree of freedom to test the claim about the value of the standard deviation;

X² = (n-1) s²/ б² = (16-1)(1.6)² / (2)² = 9.6

taking the P value of X² (9.6) for 15 D O F  from the P value table gives us

1-0.8441 = 0.1559

also ∝ = 0.05

where P-value > ∝ (0.05)

we can see from here that there is insufficient evidence to claim that new suit is better than that of the original suit, having failed to neglect H₀

(b). Given n = 100 and s = 1.6

then we have that X² = (n-1) s²/ б² = (100-1)(1.6)² / (2)² = 63.36

P-value of X² at 99 dif gives 0.0020

where ∝ = 0.05

since P value < ∝

rejecting the null hypothesis H₀,

we can safely say that there is sufficient claim that the new suit is better than the original at 95%.

(c). where we have that ∝ = 0.001

for part(b) P-values = 0.0020

given P-value > ∝ ;

we fail to neglect the null hypothesis.

From this we can say that the is insufficient evidence backing the claim thhat the new suit is better than the original suit at 99.99% confidence level.

cheers i hope this helps!!!!!

5 0
3 years ago
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