A. In the diagram above, angles ABCABC and CBDCBD are

? A mug can hold 13.46 oz of coffee without overflowing. The radius of the mug is 3 cm. Given that 1 cm3 equals 0.034 oz, what i

Elan Coil [88]

Answer:

14 cm

Step-by-step explanation:

Given:

A mug can hold 13.46 oz of coffee.

The radius of the mug is 3 cm.

Given that 1 $cm^{3}$ equals 0.034 oz.

Question asked:

What is the height of the mug to the nearest centimeter ?

Solution:

Given that 1 $cm^{3}$ equals 0.034 oz.

By unitary method:

0.034 oz = 1 $cm^{3}$

1 oz = $\frac{1}{0.034}$

13.46 oz = $\frac{1}{0.034}\times13.46 =395.88 \ cm^{3}$

A mug can hold 13.46 oz of coffee means volume of cylinder is given which is 395.88 $cm^{3}$ . Now we can find the height of the mug by using volume of cylinder formula:

volume of cylinder = $\pi r^{2} h$

$395.88=\frac{22}{7} \times3\times3\times \ h\\395.88=\frac{198 \ h}{7}$

By cross multiplication:

$395.88\times 7 =198\ h\\2771.16= 198\ h$

By dividing both side by 198

$h = 13.99$ $cm$

Therefore, height of the mug to the nearest centimeter is 14 cm.

6 0

3 years ago

Read 2 more answers

An angle through 1/6 of circle. What is the measure of this angle?

azamat

Answer:

60 degrees

Step-by-step explanation:

4 0

3 years ago

What is the equation that represents the scenario?

miskamm [114]

Answer:y=5x

Step-by-step explanation:

B

7 0

3 years ago

Scientists were studying a rare species of parrot. They went to a forest in the year

Brrunno [24]

Answer:

$P(t) = 608(1.5)^{t}$

Step-by-step explanation:

The number of parrots in t years after 2010 can be modeled by the following function:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the number of parrots in 2010 and r is the growth rate, as a decimal.

608 parrots in the forest in 2010.

This means that $P(0) = 608$

Then

$P(t) = 608(1+r)^{t}$

When the scientists went back 5 years later, they found 4617 parrots.

This means that $P(5) = 4617$

We use this to find 1 + r. So

$P(t) = 608(1+r)^{t}$

$4617 = 608(1+r)^{5}$

$(1+r)^{5} = \frac{4617}{608}$

$1 + r = \sqrt[5]{\frac{4617}{608}}$

$1 + r = 1.5$

So

$P(t) = 608(1.5)^{t}$

8 0

3 years ago

A hypothesis test is conducted at the .05 level of significance to test whether or not the population correlation is zero. If th

finlep [7]

Answer:

Th computed value of the test statistic is 3.597

Step-by-step explanation:

The null and the alternative hypothesis is as follows:

Null Hypothesis:

$\mathbf{H_o:}$ the population correlation coefficient is equal to zero

$\mathbf{H_a:}$ the population correlation coefficient is not equal to zero

The test statistics for Pearson correlation coefficient is thus computed as :

$t =\dfrac{r \sqrt{(n-2)}} { \sqrt{(1-(r)^2)} }$

where;

r = correlation coefficient = 0.60

n = sample size = 25

So;

$t =\dfrac{0.60 \sqrt{(25-2)}} { \sqrt{(1-(0.60)^2)} }$

$t =\dfrac{0.60 \sqrt{(23)}} { \sqrt{(1-0.36} }$

$t =\dfrac{0.60 *4.796} {0.8}$

t = 3.597

Comparing to a critical value of t (23 degrees of freedom two-tailed value) = 2.069

Decision Rule:

Since computed value of t is greater than the critical value of t; We reject the null hypothesis and accept the alternative hypothesis.

Conclusion:

We conclude that the population correlation coefficient significantly differs from 0 at 5% (0.05) level of significance.

6 0

3 years ago