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Arada [10]
3 years ago
9

Assuming that $3u + 12v\neq0$, simplify $\dfrac{12u^3 + 48u^2v}{3u+12v}$.

Mathematics
1 answer:
Kay [80]3 years ago
5 0

Answer:

  4u²

Step-by-step explanation:

  \dfrac{12u^3 + 48u^2v}{3u+12v}=\dfrac{12u^2(u+4v)}{3(u+4v)}=\boxed{4u^2}

Common factors cancel from numerator and denominator. The one factor that might make the expression undefined is given as non-zero, so no additional restrictions apply.

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Answer:

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Step-by-step explanation:

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2) Collect like terms.

{x}^{2}  + (5x + 4x) + 20

3) Simplify.

{x}^{2}  + 9x + 20

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3 years ago
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2 years ago
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If a kilowatt-hour of energy costs 75 cents, how much does it cost to leave a 40-watt light bulb on for the entire month of May
spin [16.1K]
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Answer:

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     2

Step-by-step explanation:

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