Check the picture attached
let the rays forming angle T be ray 1 and ray 2
Draw a circle with center point T. Let the intersection of the circle with rays 1 and 2 be at points A and B respectively.
Draw 2 circles with centers A and <span>B so that:
The radii (radius'es) are equal, and they are large enough to intersect.
Denote the intersection of these 2 circles with C.
Join T to C. The line through T and C is the bisector.</span>
0.4a=80
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0.4 0.4
a=200
Where a is the number times 40%, which is 0.4 in decimal form.
The answer will be as shown in the pic 15x^(2) +35x
First factor the numerator
b^2-6b+8/b-4 * b+8/b-2
u will get
(b-2)(b-4)/(b-4)*(b-2)*b+8
those will cancel out each other will left only
b+8<span />