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Anna007 [38]
3 years ago
11

Which algebraic expression is a difference with two terms?

Mathematics
1 answer:
dlinn [17]3 years ago
5 0

Evaluating an algebraic expression means to calculate the expression given a certain variable. Sometimes a problem will ask you to do this; most of the time, however, you will want to evaluate an expression to check your own algebra work. As long as you understand the basic terms and rules of algebra, evaluating an expression is a simple process.

 this is the most info i can give u

Identify the parts of an algebraic expression. An algebraic expression is a set of numbers and letters combined by mathematical operations, such as addition, subtraction, division, and multiplication. The numbers in the expression are called constants or coefficients, depending on their function. The letters are called variables.[1]

2x}2x is an expression. In this expression, you are multiplying the coefficient  2} 2 by the variable x}x.

2x+3y}2x+3y is an expression called a binomial. In this expression, you add the product of 3y}3y to the product of  2x}2x. In this expression, 2} 2 and  3}3 are coefficients, and x}x and  y}y are variables.

Once you add an equal sign to an expression, it becomes an equation. For example, 2x=14}2x=14 is an equation.

Image titled Evaluate an Algebraic Expression Step 2

2

Understand what a variable is. A variable is a symbol, usually a letter, that stands for an unknown value.[2] In algebra, you are usually trying to find the value of the variable. In order to evaluate an algebraic expression, however, you need to be given the variable’s value.

Image titled Evaluate an Algebraic Expression Step 3

3

Determine how to evaluate the expression. Evaluate means to simplify an expression. When you are asked to evaluate an algebraic expression, you need to plug a given value for the variable into the expression and solve.[3]

For example, you might be asked to evaluate  2x}2x when x=2}x=2.

Part

2

Evaluating an Expression with One or Two Variables

Image titled Evaluate an Algebraic Expression Step 4

Identify the variable and its value. This information should be given to you. Usually you will be told to evaluate the expression “when” or “where” the variable is equal to a certain value. If you are not given the variable’s value, you cannot evaluate the expression.

For example, you might be asked to evaluate the expression 5x-10}5x-10 when  x=8}x=8.

Substitute the given value for the variable. To do this, plug the given value into the expression wherever you see the variable. If the variable has a coefficient (a number you need to multiply its value by), make sure to put the value in parentheses.

For example, to evaluate  5x-10}5x-10 when x=8}x=8, replace the x}x in the equation with  8}8: 5(8)-10}5(8)-10.

Image titled Evaluate an Algebraic Expression Step 6

Complete the necessary calculations. Remember to follow the order of operations when solving an expression. When you complete your calculations rewrite the expression as an equation.

For example:

5(8)-10}5(8)-10

=40-10}=40-10

=30}=30

So,  5(8)-10=30}5(8)-10=30.

Image titled Evaluate an Algebraic Expression Step 7

Evaluate an expression with Two Variables. To do this, follow the same steps as you do for evaluating an expression with one variable, except plug in the values for both variables into the equation. These values should be given.

Make sure you do not switch the values. The x value cannot be substituted for they}y variable and vice versa. Doing so will give you an incorrect solution.

Part

Completing Sample Problems

Image titled Evaluate an Algebraic Expression Step 8

Evaluate the following expression when x=3 x=3}x=3:  2x+3}2x+3.

Identify the variable and its value. The variable is  x}x, and you are evaluating the expression for x=3}x=3.

Substitute the given value for the variable:  2(3)+3}2(3)+3.

Make the necessary calculations:  2(3)+3=6+3=9}2(3)+3=6+3=9.

Write the equation:  2(3)+3=9}2(3)+3=9

Image titled Evaluate an Algebraic Expression Step 9

2

Evaluate the following expression with two variables when x=2 x=2}x=2 and y=6 y=6}y=6: 4x+3y}4x+3y.

Identify both variables and their values. The variables are  x}x and  y}y, and you are evaluating the expression for x=2}x=2 and y=6}y=6.

Substitute both given values for the variables:4(2)+3(6)}4(2)+3(6).

Make the necessary calculations 4(2)+3(6)=8+18=26}4(2)+3(6)=8+18=26.

Write the equation:  4(2)+3(6)=26}4(2)+3(6)=26.

Image titled Evaluate an Algebraic Expression Step 10

3

Evaluate the following polynomial when x=4 x=4}x=4: 7x^{2}-12x+13}7x^{{2}}-12x+13.

Identify the variable and its value. The variable is  x}x, and you are evaluating the expression for x=4}x=4.

Substitute the given value for the variable:  7(4)^{2}-12(4)+13}7(4)^{{2}}-12(4)+13.

Make the necessary calculations. Remember when working with exponents that you should calculate the exponent before multiplying by a coefficient:

=7(16)-12(4)+13}=7(16)-12(4)+13

=112-48+13}=112-48+13

=64+13}=64+13

=77}=77

Write the equation:  7(16)-12(4)+13=77}7(16)-12(4)+13=77

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nirvana33 [79]
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5x+2+3x+8+4x-1
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3 years ago
Show how to find the roots (zeros) of the function in the picture below.
Vikki [24]

Answer:

The roots (zeros) of the function are:

x=5,\:x=-8

Step-by-step explanation:

Given the function

f\left(x\right)=x^2+3x-40

substitute f(x) = 0 to determine the zeros of the function

0=x^2+3x-40

First break the expression x² + 3x - 40  into groups

x² + 3x - 40 = (x² - 5x) + (8x - 40)

Factor out x from x² - 5x:  x(x - 5)

Factor out 8 from 8x - 40:  8(x - 5)

Thus, the expression becomes

0=x\left(x-5\right)+8\left(x-5\right)

switch the sides

x\left(x-5\right)+8\left(x-5\right)=0

Factor out common term x - 5

(x - 5) (x + 8) = 0

Using the zero factor principle

if ab=0, then a=0 or b=0 (or both a=0 and b=0)

x-5=0\quad \mathrm{or}\quad \:x+8=0

Solve x - 5 = 0

x - 5 = 0

adding 5 to both sides

x - 5 + 5 = 0 + 5

x = 5

solve x + 8 = 0

x + 8 = 0

subtracting 8 from both sides

x + 8 - 8 = 0 - 8

x = -8

Therefore, the roots (zeros) of the function are:

x=5,\:x=-8

6 0
2 years ago
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