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Pani-rosa [81]
3 years ago
5

In the graph line ( ) passes through the complex number 1+2i and the line( ) passes through -2+2i

Mathematics
2 answers:
Nikitich [7]3 years ago
7 0
Line E, line G.

_____
posledela3 years ago
6 0
Line E, Line G is the best answer
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If f(x)= -2 , what is x?
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Find the value of r in (4,r),(r2) so that the slope of the line containing them is -5/3 A.-1/7 B-7. C 1/7 D. 7
inessss [21]

Answer:

Option D (7).

Step-by-step explanation:

The formula for gradient of the straight line is given by:

m = (y2 - y1)/(x2 - x1); where (x1, y1) and (x2, y2) are two fixed points on the straight line. It is given that (x1, y1) = (4, r) and (x2, y2) = (r, 2). The gradient of the straight line is given by -5/3. To find the value of r, simply substitute all the values in the gradient equation. Therefore:

-5/3 = (2 - r)/(r - 4).

Cross Multiplying:

-5*(r - 4) = 3*(2 - r).

-5r + 20 = 6 - 3r.

-2r = -14.

r = 7.

Therefore, Option D is the correct answer!!!

4 0
3 years ago
Read 2 more answers
If (x)=3x-1 and s(x)=2x+1, which expression is equivalent to r over s (6) ?
katrin [286]

Answer:

\large\boxed{\dfrac{3(6)-1}{2(6)+1}}

Step-by-step explanation:

\left(\dfrac{f}{g}\right)(x)=\dfrac{f(x)}{g(x)}\\\\\text{We have}\\\\f(x)=3x-1,\ g(x)=2x+1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x-1}{2x+1}\\\\\left(\dfrac{f}{g}\right)(6)\to\text{put x = 6 to the equation of the function}\ \left(\dfrac{f}{g}\right)(x):\\\\\left(\dfrac{f}{g}\right)(6)=\dfrac{3(6)-1}{2(6)+1}

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3 years ago
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JulsSmile [24]
$2 because .200 *20 = 4 and half of 4 is 2

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3 years ago
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