Answer:
Option (b) Both are polymers of D-glucose but cellulose is connected by ( beta 1-4 ) glycosidic linkage whereas glycogen is connected by ( alpha1-4) glycosidic linkage....
Explanation:
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I don’t know any famous ecologists but I know their knowledge impacts us today because we wouldn’t know that much about how and why life forms interact with their habitats
Answer:
Explanation:
Using Ohm's law
V ( voltage) = I (current A) × Resistance R in ohms
R = 7.0 × 10⁹Ω
V = 80 mV = 80 / 1000 = 0.08 V
0.08 V = I × 7.0 × 10⁹Ω
a) I = 0.08 V / 7.0 × 10⁹Ω = 1.142857 × 10 ⁻¹¹ A
b) quantity of charge = I × t = 1.142857 × 10 ⁻¹¹ A × 0.85 s = 9.7142857 × 10⁻¹² C
number of Na⁺ ions ( q = +e) = 9.7142857 × 10⁻¹² C / 1.6 × 10⁻¹⁹ C = 60714285.714 Na⁺ ions
There are several ways;
The Skeletal system protects for example the heart and several aspects of large vasculature. The skeleton also has the means to produce blood cells in the marrow of some of the bones.
The shoreline is one of the harshest and most changeable environments for living creatures. The changing tides shift the environment dramatically within a sub-daily cycle. Here, we can consider two typical shoreline organisms, and the changing environment they must endure. Within the rocky shore environment, an octopus would be within the shallow but open sea environment during high tide, and water temperature and salinity conditions would be fairly constant. During low tide, the octopus might become trapped in a rock pool. This environment is dramatically different. The water temperature and salinity might increase drastically with exposure to solar radiation. The octopus is also more vulnerable to predation by humans and other land animals. Within the sandy shore environment, sand clams would be actively positioned at the interface of the sand and water, and will be actively filtering sea water for detritus. During low tide, the sand would be exposed to the air, and the clams would burrow down into the sand so as to avoid dessication.
