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timurjin [86]
3 years ago
12

Find the product of z1 and z2, where z1 = 5(cos 60° + i sin 60°) and z2 = 7(cos 210° + i sin 210°)

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

cos210=cos(180+30)=−cos30=−√32 . sin210=sin(180+30)=−sin30=−12 . 3(cos210+isin210) =3(−√32)+3i(−12). −(32)√3−(32)i. My favourite way of seeing that sin30=12 and cos30=√32 is ...

Step-by-step explanation:

But that's what I say personally

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5x + 8 - 7x = -4x + 1
irakobra [83]

Step-by-step explanation:

5x+8-7x=4x+1

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6 0
3 years ago
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Plz help me with this problem
Evgen [1.6K]
First we rearrange by using the definition of between.
AB=x+10, BC=x+14, AC=22
Given that AB+BC=AC, we can solve for X
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3 0
3 years ago
Help me solve those show work 3(2a-5)=12-7a, 27=3c-3(6-2c)and 6c-8-2c=-16
posledela
3(2a-5) = 12-7a
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3 0
3 years ago
Solve for x does anyone know how to do this?​
riadik2000 [5.3K]

Answer:

x = 9

Step-by-step explanation:

The sum of the 4 angles in a quadrilateral = 360°

Sum the given angles and equate to 360

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x = 9

6 0
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