3 years ago

Find the product of z1 and z2, where z1 = 5(cos 60° + i sin 60°) and z2 = 7(cos 210° + i sin 210°)

1 answer:

3 0

Answer:

cos210=cos(180+30)=−cos30=−√32 . sin210=sin(180+30)=−sin30=−12 . 3(cos210+isin210) =3(−√32)+3i(−12). −(32)√3−(32)i. My favourite way of seeing that sin30=12 and cos30=√32 is ...

Step-by-step explanation:

But that's what I say personally

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The sum of 2112 + 2212 + 2312 when divided by 4, leaves no remainder. What will be the remainder when the sum of 2113 + 2213 + 2

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Step-by-step explanation:

2112 + 2212 + 2312 / 4 leaves no remainder, as already the individual numbers could be divided by 4 without remainder.

2113 = 2112 + 1

2213 = 2212 + 1

so, we get a remainder of +1 and +1 for these 2 numbers, so we get in total a remainder of +2.

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Step-by-step explanation:

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First find the amount of each payment:
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