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timurjin [86]
3 years ago
12

Find the product of z1 and z2, where z1 = 5(cos 60° + i sin 60°) and z2 = 7(cos 210° + i sin 210°)

Mathematics
1 answer:
Verizon [17]3 years ago
3 0

Answer:

cos210=cos(180+30)=−cos30=−√32 . sin210=sin(180+30)=−sin30=−12 . 3(cos210+isin210) =3(−√32)+3i(−12). −(32)√3−(32)i. My favourite way of seeing that sin30=12 and cos30=√32 is ...

Step-by-step explanation:

But that's what I say personally

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−2⋅f(−6)−7⋅g(−7) = ?
antiseptic1488 [7]

Answer: +12f +49g

-2f(-6)-7g(-7)

3 0
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Zach can read 7pages of a book in 5 minutes at this rate how long will it take him to read 175 pages
AlexFokin [52]
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5 0
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A rectangular prism has a length of 18 feet, a height of 14 feet, and a width of 2 feet. What is its volume, in cubic feet?
Fittoniya [83]

Answer:

504

Step-by-step explanation:

14x18x2=

(14x18)x2=

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6 0
2 years ago
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Please help ( the function table)
Norma-Jean [14]
Hope this will help

8 0
3 years ago
Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
3 years ago
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