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Anna [14]
3 years ago
10

To combat piracy, many software publishers require users to type in a(n) ____ code, a sequence of numbers and letters in order t

o complete an installation.
Computers and Technology
1 answer:
babymother [125]3 years ago
6 0

To combat piracy, many software publishers require users to type in a validation code, a sequence of numbers and letters in order to complete an installation. It is referred to as Card Validation Code (CVC). This series of numbers provides an additional layer of security to prevent fraud.

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2.36 LAB: Warm up: Variables, input, and casting (1) Prompt the user to input an integer, a double, a character, and a string, s
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Answer:

The entire program is:

#include <iostream>

using namespace std;

  int main() {          

  int userInt;

  double userDouble;

  char userChar;

  string userString;  

  cout<<"Enter integer:"<<endl;

  cin>>userInt;  

  cout<<"Enter double:"<<endl;

  cin>>userDouble;  

  cout<<"Enter character:"<<endl;

  cin>>userChar;  

  cout<<"Enter string:"<<endl;

  cin>>userString;    

 cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl;

 cout<<endl;  

   cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl;  

cout<<endl;

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt<<endl<<userDouble<<" cast to an integer is "<<(int)userDouble;  

  return 0;  }

The program in C language:

#include <stdio.h>  

int main() {

  int userInt;  

  double userDouble;  

  char userChar;  

  char userString[50];

  printf("Enter integer: \n");  

  scanf("%d", &userInt);

  printf("Enter double: \n");  

  scanf("%lf", &userDouble);

  printf("Enter character: \n");  

  scanf(" %c", &userChar);  

  printf("Enter string: \n");  

  scanf("%s", userString);  

  printf("%d %lf %c %s\n", userInt, userDouble, userChar, userString);

  printf("\n");

  printf("%d %lf %c %s\n%s %c %lf %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt);

  printf("\n");

  printf("%d %lf %c %s\n%s %c %lf %d\n%lf cast to an integer is %d \n", userInt, userDouble, userChar, userString, userString, userChar, userDouble, userInt, userDouble, (int)userDouble);  }

Explanation:

Lets do the program step by step:

1)  Prompt the user to input an integer, a double, a character, and a string, storing each into separate variables. Then, output those four values on a single line separated by a space:

Solution:

The program is:

#include <iostream>  //to use input output functions

using namespace std;  //to identify objects cin cout

  int main() {  //start of main method

  //declare an integer, a double, a character and a string variable  

  int userInt;  //int type variable to store integer

  double userDouble;  //double type variable to store double precision floating point number

  char userChar;  //char type variable to store character

  string userString;  //string type variable to store a string

  cout<<"Enter integer:"<<endl;  //prompts user to enter an integer

  cin>>userInt;  //reads the input integer and store it to userInt variable

  cout<<"Enter double:"<<endl;  //prompts user to enter a double type value

  cin>>userDouble;  //reads the input double value and store it to userDouble variable

  cout<<"Enter character:"<<endl;  //prompts user to enter a character

 cin>>userChar; //reads the input character and store it to userChar variable

  cout<<"Enter string:"<<endl;  //prompts user to enter a string

  cin>>userString; //reads the input string and store it to userString variable

   

cout<<userInt<<" "<<userDouble<<" "<<userChar<<" "<<userString<<endl; //output the values on a single line separated by space

So the output of the entire program is:

Enter integer:                                                                                                                                99                                                                                                                                            Enter double:                                                                                                                                 3.77                                                                                                                                          Enter character:                                                                                                                              z                                                                                                                                             Enter string:                                                                                                                                 Howdy                                                                                                                                         99 3.77 z Howdy

(2) Extend to also output in reverse.

Now the above code remains the same but add this output (cout) statement at the end:

  cout<<userString<<" "<<userChar<<" "<<userDouble<<" "<<userInt;

Now the output with the same values given as input is:

Enter integer:                                                                                                                                  99                                                                                                                                              Enter double:                                                                                                                                   3.77                                                                                                                                            Enter character:                                                                                                                                z                                                                                                                                               Enter string:                                                                                                                                   Howdy  

99 3.77 z Howdy                                                                                                                                     Howdy z 3.77 99

(3) Extend to cast the double to an integer, and output that integer.

The rest of the code remains the same but add the following output (cout) statement in the end:

cout<<userDouble<<" cast to an integer is "<<(int)userDouble;

Now the output with the same values given as input is:

Enter integer:                                                                                                                                  99                                                                                                                                              Enter double:                                                                                                                                   3.77                                                                                                                                            Enter character:                                                                                                                                z                                                                                                                                               Enter string:                                                                                                                                   Howdy                                                                                                                                           99 3.77 z Howdy                                                                                                                                 Howdy z 3.77 99                                                                                                                                 3.77 cast to an integer is 3  

3 0
3 years ago
What does my name look like in binary code, btw my mane is Wendy Alexis Morales
jekas [21]
01010111 01100101 01101110 01100100 01111001 00100000 01000001 01101100 01100101 01111000 01101001 01110011 00100000 01001101 01101111 01110010 01100001 01101100 01100101 01110011
6 0
3 years ago
Read 2 more answers
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