How to find slope of parabola at a point?

1 answer:

4 0

To find the slope of a parabola at a point you have to find is the first derivative of the function. This first derivative is the slope of the tangent of the parabola at the given point and it is the same slope of the parabola.

If you have the parabola with the general form y = Ax^2 + Bx + C

The slope at point (m,n) is:

y' = 2Ax + B

x = n

=> y ' = 2A(n) + B.

For example, find the slope of the parabole y = 3x^2 + 2x + 1, at x = 1

y' = 6x + 2

x = 1 => y' = 6(1) + 2 = 8.

So the slope at x = 1 is 8.

You might be interested in

Find all solutions in the interval [0, 2π). (sin x)(cos x) = 0

Deffense [45]

$\bf sin(x)cos(x)=0\implies 
\begin{cases}
sin(x)=0\\
\measuredangle x=sin^{-1}(0)\\
\measuredangle x=0\ ,\ \pi \\
----------\\
cos(x)=0\\
\measuredangle x=cos^{-1}(0)\\
\measuredangle x=\frac{\pi }{2}\ ,\ \frac{3\pi }{2}
\end{cases}$

3 0

3 years ago

Read 2 more answers

5,3 = 28 7,6 = 55 4,5 = 21 3,8 = ?

Bond [772]

Answer:

Step-by-step explanation:

3×3+8

i applied BODMASS RULE

5 0

2 years ago

Anyone know the area??

Diano4ka-milaya [45]

Area= 1/2(base)(height)
A= 1/2(7)(2)
A= (1*2*7)/2
A= 14/2
A= 7 units squared

Hope this helps! :)

3 0

3 years ago

Explain how to calculate the surface area of a composite figure in your own words.

AleksAgata [21]

To calculate the surface area of a composite figure you must apply the formulas for calculate the area of each figure that is part of the composite figure and then, you must sum all the areas calculated.

For example, is the composite figure is form by a triangle and rectangle, the surface area of the composite figure will be:

SA= Area of the triangle+ Area of the rectangle= (bh/2)+bh

8 0

3 years ago

Read 2 more answers

Simplify each express 11. b-4c9d6

marshall27 [118]

Look give me ......................... pls

4 0

3 years ago