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AlexFokin [52]
3 years ago
9

Can anyone please help me?

Mathematics
2 answers:
Ket [755]3 years ago
8 0
Angle 3 equals angle 2. They are not supplementary.
meriva3 years ago
7 0
Answer c 


this is for 20 characters
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erastovalidia [21]
Your answer is 9s^2-9st+6st-6t^2
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3 years ago
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9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
2 years ago
The cost of off-campus living for U of O students is normally distributed. The Office of the Registrar estimates that on average
evablogger [386]

Answer:

H1 : μ < 1225

Step-by-step explanation:

The alternative hypothesis in carrying out a statistical test could be explained as a notion which aims to displace or rival an initial position, the null hypothesis.

When declaring an hypothesis, the statement compares the initial or population mean in the hypothesis statement and not the result or outcome of the sample statistic.

In the scenario above :

The null is of the notion that :

H0 : μ = 1225 ;

Hence, the stance of the alternative which is that the mean is lower or less will be written as :

H1 : μ < 1225

6 0
3 years ago
What os the domain of the given function
kramer
I need to see the function In order to do this
6 0
3 years ago
Question 1
Black_prince [1.1K]
C:x, in the bottom equation
4 0
2 years ago
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