Your answer is 9s^2-9st+6st-6t^2
Answer:
Here's what I get.
Step-by-step explanation:
9. (6, -8)
The reference angle θ is in the fourth quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100
OB = √100 = 10
10. cot θ = -(√3)/2
The reference angle θ is in the second quadrant.
∆AOB is a right triangle.
OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7
OB = √7
Answer:
H1 : μ < 1225
Step-by-step explanation:
The alternative hypothesis in carrying out a statistical test could be explained as a notion which aims to displace or rival an initial position, the null hypothesis.
When declaring an hypothesis, the statement compares the initial or population mean in the hypothesis statement and not the result or outcome of the sample statistic.
In the scenario above :
The null is of the notion that :
H0 : μ = 1225 ;
Hence, the stance of the alternative which is that the mean is lower or less will be written as :
H1 : μ < 1225
I need to see the function In order to do this
C:x, in the bottom equation
