PLEASE HELP!! I don't really know how to solve this.

Mathematics

1 answer:

Yakvenalex [24]2 years ago

4 0

Answer:

x=13

y=14

Step-by-step explanation:

We know that angle JNK is equal to angle MNL. We also know that angle JNK and angle KNL are supplementary.

Knowing this, we can write two equations: $4x-1=3y+9$ and $(4x-1)+(2x+6y+19)=180$ . We can solve for y in the first equation. Subtracting 9 from both sides gives us $4x-10=3y$ . Dividing both sides by 3 gives us $\frac{4x-10}{3} =y$ .

We can plug that in to the second equation to get $(4x-1)+(2x+6(\frac{4x-10}{3} )+19)=180$ . Expanding the second parenthesis, we get $2x+8x-20+19$ which equals $(10x-1)$ . We now have $(4x-1)+(10x-1)=180$ . Expanding gives us $14x-2=180$ . Adding 2 to both sides gives us $14x = 182$ . Dividing both sides by 14 gives us $x=13$ .

We can now plug 13 into the above equation to solve for y. $y= \frac{4*13-10}{3}$ Solving that gives you $y=14$ .

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Assume that f is continuous on [-4,4] and differentiable on (-4,4). The table gives some values of f'(x) x: -4, -3, -2, -1, 0, 1

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