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3 years ago

PRECALCULUS, PLEASE HELP!

Mathematics

1 answer:

solmaris [256]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

If n is even, sum = n/2.

If n is odd, sum = (n-1)/2 - 16

Discussion:

See attached doc and ask questions!

Thank you,

MrB

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A cube with each face a different colour will fit exactly into a box in which it is packaged. In how many ways can the cube be p

dmitriy555 [2]

Answer:

362880 times

I hope this helps

4 0

3 years ago

Log based question, i just need help with parts b and c

Tanya [424]

Answer:

b) There is translation 3 units to the right and 1 unit up

c) The domain is {x I x > 3}

The equation of the asymptote is x = 3

Step-by-step explanation:

* Lets revise the rule of the translation

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

b) ∵ f(x) = $log_{2} (x-3)+1$

∵ The parent function is $log_{2} x$

∴ x is changed to (x - 3), that means there is a translation 3 units

to the right

∵ We add the parent function by 1, that means there is a translation

1 unit up

* There is translation 3 units to the right and 1 unit up

c) To find the domain of the function, find the values of x which

make the function undefined

∵ $log_{2}(0)$ is undefined

∴ x - 3 can not be 0

∵ x - 3 = 0 ⇒ add 3 to both sides

∴ x = 3

∴ The domain of the function is all real number greater than 3

* The domain is {x I x > 3}

∵ x can not be 3

∴ There is a vertical asymptote, its equation is x = 3

* The equation of the asymptote is x = 3

# Look to the attached graph for more understand for the domain

and the equation of the asymptote

4 0

3 years ago

Give an example of a function with both a removable and a non-removable discontinuity.

navik [9.2K]

Answer:

(x+5)(x-3) / (x+5)(x+1)

Step-by-step explanation:

A removeable discontinuity is always found in the denominator of a rational function and is one that can be reduced away with an identical term in the numerator. It is still, however, a problem because it causes the denominator to equal 0 if filled in with the necessary value of x. In my function above, the terms (x + 5) in the numerator and denominator can cancel each other out, leaving a hole in your graph at -5 since x doesn't exist at -5, but the x + 1 doesn't have anything to cancel out with, so this will present as a vertical asymptote in your graph at x = -1, a nonremoveable discontinuity.

8 0

3 years ago

A video store charges $12 for used games and $25 for new games. Jonathan has saved $300 to spend on video games. This scenario i

gavmur [86]

Answer:

25 used games

Step-by-step explanation:

Divide his money by the price for one used game

300/12

3 0

3 years ago

Read 2 more answers