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Eduardwww [97]
3 years ago
12

PLEASE HELP!!! It says to find the area of the shaded sector rounded to the nearest hundredth

Mathematics
1 answer:
arlik [135]3 years ago
6 0

Answer:

402.12 cm²

Step-by-step explanation:

45 degrees is 1/8 of a circle

πr² = whole circle

1/8*(3.1415926....)(32)² = 402.12 cm²

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If a third plane could be drawn which contains both lines a and b, then what must the lines be?
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Lines AC←→ and DB←→ intersect at point W. Also, m∠DWC=138° .
mr_godi [17]

m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°

Solution:

Line \overrightarrow{A C} \text { and } \overrightarrow{B D} intersect at a point W.

Given m \angle D W C=138^{\circ}.

<em>Vertical angle theorem:</em>

<em>If two lines intersect at a point then vertically opposite angles are congruent.</em>

<u>To find the measure of all the angles:</u>

∠AWB and ∠DWC are vertically opposite angles.

Therefore, ∠AWB = ∠DWC

⇒ ∠AWB = 138°

Sum of all the angles in a straight line = 180°

⇒ ∠AWD + ∠DWC = 180°

⇒ ∠AWD + 138° = 180°

⇒ ∠AWD = 180° – 138°

⇒ ∠AWD = 42°

Since ∠AWD and ∠BWC are vertically opposite angles.

Therefore, ∠AWD = ∠BWC

⇒ ∠BWC = 42°

Hence the measure of the angles are

m∠DWC=138°, ∠AWB = 138°, ∠AWD = 42°, ∠BWC = 42°.

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3 0
2 years ago
Use the limits to find the area between the curve and the X-axis for the given interval y = x ^ 3 from x = 0 to x = 1
viva [34]

Answer:

1/4

Step-by-step explanation:

D

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3 years ago
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