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Colt1911 [192]
2 years ago
15

Evaluate the limit by first recognizing the sum as the Riemann sum for a function defined on the interval [0,1]: lim as n approa

ches infinity (1/n)((sqrt(1/n)+(sqrt(2/n)+(sqrt(3/n)+...............+(sqrt(n/n))
Mathematics
1 answer:
mina [271]2 years ago
3 0
\lim_{n \to +\infty} \left ( \dfrac{1}{n} \cdot \left ( \sqrt{ \dfrac{1}{n} } + \sqrt{ \dfrac{2}{n} } + \sqrt{ \dfrac{3}{n} } + \cdots + \sqrt{ \dfrac{n}{n} }} \right ) \right ) =

\dfrac{1}{n} \sum_{i = 1}^n \left (  \sqrt{ \dfrac{i}{n} }   \right ) =  \int\limits^1_0 { \sqrt{x} } \, dx  =  \left [  \frac{2}{3}x^{ \frac{3}{2} }       \right ]^{1}_{0} =   \dfrac{2}{3} \cdot 1^{ \frac{3}{2} }  -  \dfrac{2}{3} \cdot 0^{ \frac{3}{2} }  =  \boxed{ \dfrac{2}{3} }
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Deffense [45]

Answer:

no lol i wish i did ahhahahha

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2 years ago
An 8 foot square floor is to be covered with square tiles measuring 8 inches on each side. If each tile costs 50 cents, how much
wariber [46]

9514 1404 393

Answer:

  (c) $72

Step-by-step explanation:

Each tile is 8/12 ft = 2/3 ft on a side. Then 8/(2/3) = 12 tiles will fit along each edge of the square area to be tiled. That is ...

  12 × 12 = 144

tiles will be needed to cover the area.

The cost of 144 tiles at $0.50 each is ...

  (144)($0.50) = $72.00

8 0
2 years ago
4. The numencal coefficient in 3xy is<br>A-3<br>В 2<br>D ху<br>Ску​
BabaBlast [244]

Answer:

3

Step-by-step explanation:

Because in 3xy 3 is the numerical coefficient

3 0
3 years ago
Read 2 more answers
Can someone help me with this problem please? Thank you!
Olenka [21]

Answer:

50

Step-by-step explanation:

since the Pythagorean theorem is

c= √a^2+b^2

b is the bottom line (48)

a is the right line (14)

c is the top line (c)

plug that in

c = √14^2 + 48^2

then do the exponets

14^2 = 14 * 14 = 196

48^2 = 48 * 48 = 2304

then add them together

196 + 2304 = 2500

c = √2500

the sqrt of 2500 is 50 (50 * 50 = 2500)

c = 50

your answer is 50

hope this helps:)

6 0
1 year ago
Read 2 more answers
One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0
3 years ago
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