Answer:

• let f(x) be m:

• make x the subject of the function:
![{ \rm{8m = {x}^{3} + 128}} \\ \\ { \rm{ {x}^{3} = 8m - 128 }} \\ \\ { \rm{ {x}^{3} = 8(m - 16) }} \\ \\ { \rm{x = \sqrt[3]{8} \times \sqrt[3]{(m - 16)} }} \\ \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}](https://tex.z-dn.net/?f=%7B%20%5Crm%7B8m%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%20128%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7B%20%7Bx%7D%5E%7B3%7D%20%3D%208m%20-%20128%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7B%20%7Bx%7D%5E%7B3%7D%20%3D%208%28m%20-%2016%29%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Bx%20%3D%20%20%5Csqrt%5B3%5D%7B8%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%28m%20-%2016%29%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Bx%20%3D%202%20%5Csqrt%5B3%5D%7B%28m%20-%2016%29%7D%20%7D%7D)
• therefore:

What triangle? you need to show the triangle
The lowest possible denominator of 1/8 is 1/8.
1/8 can't be simplified anymore making this the smallest possible denominator.
It is hard to comprehend your question. As far as I understand:
f(x,y) = e^(-x)
Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.
That is all I understood. It would be easier to understand with a picture or some kind of visual aid.
Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

Now evaluate,

which evaluates to, 5/6 if I did the math correct. Correct me if I am wrong.
Now integrate this w.r.t. y:

So,

Answer:
3.5 seconds.
Step-by-step explanation:
because i just took the test.