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yulyashka [42]
3 years ago
13

What is expression for 1/4y+3/8 factored

Mathematics
1 answer:
Llana [10]3 years ago
3 0
1/4*x=3/8

1*x=3*4/8

X=12/8

3/2
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What is the inverse of the function g(x) = x^3/8 + 16 ?
lesya692 [45]

Answer:

\hookrightarrow \: { \rm{f(x) =  \frac{ {x}^{3} }{8}  + 16}} \\

• let f(x) be m:

{ \rm{m =  \frac{ {x}^{3} }{8}  + 16}} \\

• make x the subject of the function:

{ \rm{8m =  {x}^{3}  + 128}} \\  \\ { \rm{ {x}^{3} = 8m - 128 }} \\  \\ { \rm{ {x}^{3} = 8(m - 16) }} \\  \\ { \rm{x =  \sqrt[3]{8}  \times  \sqrt[3]{(m - 16)} }} \\  \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}

• therefore:

{ \boxed{ \rm{ {f}^{ - 1} (x) = 2 {(m - 16)}^{ \frac{1}{3} } }} }\\

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What is the lowest denominator of 1/8?
MissTica
The lowest possible denominator of 1/8 is 1/8.

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3 0
3 years ago
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Find the volume of the following solid. The solid between the cylinder ​f(x,y)equals=e Superscript negative xe−x and the region
PilotLPTM [1.2K]

It is hard to comprehend your question. As far as I understand:

f(x,y) = e^(-x)

Find the volume over region R = {(x,y): 0<=x<=ln(6), -6<=y <= 6}.

That is all I understood. It would be easier to understand with a picture or some kind of visual aid.

Anyways, to find the volume between the surface and your rectangular region R, we must evaluate a double integral of f on the region R.

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy

Now evaluate,

\int_{0}^{ln(6)}e^{-x}dx

which evaluates to,  5/6 if I did the math correct. Correct me if I am wrong.

Now integrate this w.r.t. y:

\int_{-6}^{6}\frac{5}{6}dy = 10

So,

\iint_{R}^{ } e^{-x}dA=\int_{-6}^{6} \int_{0}^{ln(6)} e^{-x}dx dy = 10

7 0
3 years ago
A rocket is launched into the air. The projectile motion of the rocket can be modeled using h(t) = 112t –16t2, where t is the ti
asambeis [7]

Answer:

3.5 seconds.

Step-by-step explanation:

because i just took the test.

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