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Vinil7 [7]
3 years ago
11

John and Jane Jones’ newborn baby girl, Leah, has just been diagnosed with galactosemia. Prior to their genetic counseling appoi

ntment, they submitted this family history: John and Jane’s older child, a son named Lee, does not have galactosemia. John is the only child of Hanna and Harry. Harry was an only child. Hanna has two older sisters, Hope (the oldest) and Holly. Both Harry and Hanna’s parents lived in good health into their 80s. Jane’s brother, Joe, is married to Jen. They have a son, Les, who is a
Biology
1 answer:
melomori [17]3 years ago
6 0

Answer: They have a son , Les who is 9 years old and healthy with myopia but not galactosemia. Les is unaffected with galactosemia.

Explanation:

From the family story, Leah is the only child affected with galactosemia while Les is unaffected and healthy.

Hanna's father and mother have three daughters and they are Hope, Holly and Banana( from oldest to youngest).

Hanan and Harry have an only son called John.

John married Jane and they have two children, Leah and Les.

Leah is girl that is affected with galactosemia and Les who is a boy and he is unaffected with galactosemia.

Jane's mother is Hilda and she has a brother called Joe. Joe married Jen and they have a son called Les.

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1. It involves multiple trials

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6. A lowercase letter

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1. Repetition, this means to do over and over. This would involve multiple trials and this is done to test the reliability of the results and determine if the hypothesis holds true or not.

2. If you put your cross in a Punnett square it would look like this:

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r     Rr   rr

Based on your problem: R = red; r = white

If the genotype would have a dominant allele (R), then the dominant trait will come out, if it has only recessive alleles (r) then the recessive trait will come out. So as you can see there are 2 red and 2 white. So the ratio would be 2:2 or 1:1.

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