A molecule with polar and nonpolar parts that only partially dissolves in water is described as amphipathic.
Mean for the <u>Geno Code 0</u> is average of those ten values ((-3.97)+(-3.99) +(-5.55)+ (-4.56) + (-4.51) + (-4.2 )+( -4.95) + (-4.56) + (-4 )+ (-5.68))/10= -4.597
Standard deviation formula is √((-3.97- (-4.597)2 )+(-3.99-(-4.597)2) +(-5.55-(-4.597)2)+ (-4.56-(-4.597)2) + (-4.51-(-4.597)2) + (-4.2-(-4.597) 2 )+( -4.95-(-4.597)2) + (-4.56-(-4.597)2) + (-4 -(-4.597)2)+ (-5.68-(-4.597)2))/10= √ (0.39+0.37+0.91+0.001+0.007+0.16+0.12+0.001+0.36+1.17)/10= √0.3489=0.59
Mean for the <u>Geno 1 </u>is -0.25 (calculated on the same way as for Geno 0 with different numbers) and standard deviation for Geno 1 is 0.65.
Mean for <u>Geno 2</u> is 5.241 and standard deviation is 1.038.
2.
If individual Phenotype_Value is 5.11, the corresponding genotype code is Geno code 2 since the value is in the range of values 5.241+- 1.
If individual Phenotype_Value is 5.03 the corresponding genotype code is also Geno code 2.
Since the standard deviation is used to measure the variation (dispersal) of set of data values (how close the values are to the mean value) we can conclude whether are random value is within a certain range.
Creation of a social utopia
