If 2 + 5i is a zero, then by the complex conjugate root theorem, we must have its conjugate as a zero to have a polynomial containing real coefficients. Therefore, the zeros are -3, 2 + 5i, and 2 - 5i. We have three zeros so this is a degree 3 polynomial (n = 3).
f(x) has the equation
f(x) = (x+3)(x - (2 + 5i))(x - (2 - 5i))
If we expand this polynomial out, we get the simplest standard form
f(x) = x^3-x^2+17x+87
Therefore the answer to this question is f(x) = x^3-x^2+17x+87
TTese are all parabolas whose axis of symmetry is the y axis. The negative coefficient means they open downwards and the positive mean they open upwards. The higher the absolute value of the coefficient is the greater the slope, so 2x^2 will be steeper than x^2 and -4x^2 will be steeper than - 2x^2.
So h(x) and j(x) are the answers.
I assume you happen to mean, what is the formula for a circle.
The formula is:
A=
Answer:
2.6
Step-by-step explanation:
its the answer trust me
-4(n - 6) = 12
n - 6 = -12/4 divide both sides by -4
n - 6 = -3
n = -3 + 6 add both sides by 6
n = 3
hope that helps, God bless!
