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MaRussiya [10]
3 years ago
9

The 15th and 21st terms of an arithmetic sequence are -67 and -97, what is the 30th term?

Mathematics
1 answer:
natka813 [3]3 years ago
7 0

I believe it would be -132.

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I am a 3 digit number. The sum of my digits is 14. My ones place is 3 times as much as my hundreds place.
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329

Step-by-step explanation:

4 0
2 years ago
Li invests money in a savings account. She wants to know the amount of simple interest that she will earn in 6 years at 3.75 per
Lisa [10]

Answer:

She needs the starting amount of money to create an equation.

Step-by-step explanation:

The formula that she can use when she has the starting amount or the y-intercept is this one: f(t)=P(1+b)^t.

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6 0
2 years ago
The GCF of 24 and 32 is
Oksana_A [137]

Start by setting up a factor tree for each number.

Factor in anyway that you'd like.

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Remember, prime numbers are numbers

with only 2 factors, 1 and the number itself.

Now write these factors in least to greatest

multiplying them separate rows.

Circle factors they have in common.

Since 3 pairs of two's match up, multiply by 2 three times to get 8.

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4 0
3 years ago
Read 2 more answers
Urgent!
boyakko [2]

Step-by-step explanation:

18.

the last one.

-4.9t² + 24.5t + 117.6 = 0

the ball starts at 117.6 meters height. then, during the first seconds the thrust upwards is adding height, until finally, with more and more seconds passing, gravity will win with a vengeance and pulls the ball down faster and faster than any other force in any other direction.

19.

the general solution for a quadratic equation

y = ax² + bx + c

is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = t

a = -4.9

b = 24.5

c = 117.6

t = (-24.5 ± sqrt(600.25 - -4×4.9×117.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 2304.96))/-9.8 =

= (-24.5 ± sqrt(2905.21))/-9.8 = (-24.5 ± 53.9)/-9.8

t1 = (-24.5 + 53.9)/-9.8 = -3

t2 = (-24.5 - 53.9)/-9.8 = 8

a negative time does not make any sense, so the real solution is : the ball reached the ground after 8 seconds.

20.

now the equation is

-4.9t² + 24.5t + 117.6 = 49

but this is quickly transformed again into a "= 0" equation :

-4.9t² + 24.5t + 68.6 = 0

t = (-24.5 ± sqrt(600.25 - -4×4.9×68.6))/-9.8 =

= (-24.5 ± sqrt(600.25 + 1344.56))/-9.8 =

= (-24.5 ± sqrt(1944.81))/-9.8 = (-24.5 ± 44.1)/-9.8

t1 = (-24.5 + 44.1)/-9.8 = -2

t2 = (-24.5 - 44.1)/-9.8 = 7

again, negative time does not make sense.

the ball will be at 49 m height after 7 seconds.

5 0
2 years ago
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