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3 years ago

Given that r || s and q is a transversal, we know that

Mathematics

2 answers:

Lemur [1.5K]3 years ago

7 0

Answer: alternate interior angles theorem

Step-by-step explanation:

mojhsa [17]3 years ago

4 0

Answer: Alternate interior angles theorem Is your answer.

Step-by-step explanation:

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A simple random sample of 90 is drawn from a normally distributed population, and the mean is found to be 138, with a standard d

bagirrra123 [75]

The 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

<h3>
How to find the confidence interval for population mean from large samples (sample size > 30)?</h3>

Suppose that we have:

Sample size n > 30
Sample mean = $\overline{x}$
Sample standard deviation = s
Population standard deviation = $\sigma$
Level of significance = $\alpha$

Then the confidence interval is obtained as

Case 1: Population standard deviation is known

$\overline{x} \pm Z_{\alpha /2}\dfrac{\sigma}{\sqrt{n}}$

Case 2: Population standard deviation is unknown.

$\overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}$

For this case, we're given that:

Sample size n = 90 > 30
Sample mean = $\overline{x}$ = 138
Sample standard deviation = s = 34
Level of significance = $\alpha$ = 100% - confidence = 100% - 90% = 10% = 0.1 (converted percent to decimal).

At this level of significance, the critical value of Z is: $Z_{0.1/2}$ = ±1.645

Thus, we get:

$CI = \overline{x} \pm Z_{\alpha /2}\dfrac{s}{\sqrt{n}}\\CI = 138 \pm 1.645\times \dfrac{34}{\sqrt{90}}\\\\CI \approx 138 \pm 5.896\\CI \approx [138 - 5.896, 138 + 5.896]\\CI \approx [132.104, 143.896] \approx [130.10, 143.90]$

Thus, the 90% confidence interval for the population mean of the considered population from the given sample data is given by: Option C: [130.10, 143.90]

Learn more about confidence interval for population mean from large samples here:

brainly.com/question/13770164

3 0

2 years ago

Pls help I dont understand. Find the inverse of this function.

lisov135 [29]

In the inverse we replace the place of x by y .

$g(x) = \sqrt[3]{x} - 3 \\ \\ x = \sqrt[3]{y} - 3 \\ \sqrt[3]{y} = x + 3 \\ y = {(x + 3)}^{3} \\ y = {(x + 3)}^{2} (x + 3) \\ y = ({x}^{2} + 6x + 9)(x + 3) \\ \\ y = {x}^{3} + 6 {x}^{2} + 9x + 3 {x}^{2} + 18x + 27 \\ \\ y = {x}^{3} + 9 {x}^{2} + 27x + 27 \\ \\ \\ g(x)^{ - 1} = {x}^{3} + 9 {x}^{2} + 27x + 27$

I hope I helped you^_^

8 0

3 years ago

A polling company took before an 5 polls in the week that a mayoral 66%,56%, 55%, 60% 63% of the total votes. That candidate rec

kap26 [50]

Answer:

6.7%

Step-by-step explanation:

In this question, we are to calculate the percentage error in in the average polling results calculated.

Firstly, what this means is that we calculate the average of the total votes.

That would be ; (66 + 56 + 55 + 60 + 63)/5 =

300/5 = 60%

we now proceed to calculate the percentage error in the company’s result.

Mathematically;

percentage error = (Actual value - expected value)/expected value * 100%

Here the actual value is 64% and the expected is 60%

% error = (64-60)/60 * 100 = 4/60 * 100 = 6.67%

This is 6.7% to the nearest tenth of a percent

6 0

3 years ago

Trisha drew a pair of line segments starting from a vertex.

Eduardwww [97]

The answer your looking for is A hope it helps ;)

8 0

3 years ago

Please Answer both questions Thank you <br><br> Love you

inessss [21]

THE ANSWER IS ALREADY IN THE COMMENTS

4 0

3 years ago