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3 years ago

What is 4.4 divided by 2.727

Mathematics

1 answer:

zlopas [31]3 years ago

5 0

1.613 jus use a calculator

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Customers enter the waiting line to pay for food as they leave a cafeteria on a first-come, first-served basis. The arrival rate

Elan Coil [88]

Answer:

The answer is B) 0.57.

Step-by-step explanation:

In this problem we have to apply queueing theory.

It is a single server queueing problem.

The arrival rate is $\lambda=4$ and the service rate is $\mu=7$ .

The proportion of time that the server is busy is now as the "server utilization"and can be calculated as:

$p=\frac{\lambda}{c\mu} =\frac{4}{1*7}=0.57$

where c is the number of server (in this case, one server).

3 0

3 years ago

Can anyone help me with this please

Vikentia [17]

Answer:

1. 3

2. 1

3. 9

4. 30

Step-by-step explanation:

1. 2*(18/12) = 3

2. 3*(5/15) = 1

3. 4*(45/20) = 9

4. 21*(10/7) = 30

4 0

2 years ago

Read 2 more answers

Help I will be marking brainliest!!!!

artcher [175]

Answer: A. 241 feet

Step-by-step explanation:

The figure shows two rectangular triangles.

These triangles are similar since they have two identical angles:

the first angle is 90 degrees;

the second angle is equal because the law of reflection states that the angle of incidence is equal to the angle of reflection.

The law of reflection states that the angle of incidence is equal to the angle of REFLECTION.

Let's make the proportion:

$\dfrac{4}{273} =\dfrac{5}{x} \\\\x=\dfrac{273 \cdot 5}{4} =341.25 \: (feet)\\$

It takes a minimum of 100 feet for a parachute to open and safely land without injury, so:

341.25 - 100 = 241.25 (feet)

241.25 ≈ 241 (feet)

8 0

2 years ago

What is the y-intercept of the graph of the equation 6x + 3y = 18?

ella [17]

<h3>My friends the answer is: </h3><h3> x-intercept(s): ( 3 , 0 ) </h3><h3>y-intercept(s): ( 0 , 6 ) </h3>

5 0

3 years ago

Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?

Mademuasel [1]

Answer:- a.The given expression is equivalent to $\frac{x^{10}y^{14}}{729}$

Given expression:- $[\frac{(3xy^{-5})^3}{(x^{-2}y^2)^{-4}}]^{-2}$

$=[\frac{(3)^3x^3y^{-5\times3}}{x^{-2\times-4}y^{2\times-4}}]^{-2}.........(a^m)^n=a^{mn}$

$=[\frac{27x^3y^{-15}}{x^8y^{-8}}]^{-2}$

$=[27x^{3-8}y^{-15-(-8)}]^{-2}............\frac{a^m}{a^n}=a^{m-n}$

$=[27x^{-5}y^{-7}]^{-2}=(27)^{-2}(x^{-5})^{-2}(y^{-7})^{-2}.........(a^m)^n=a^{mn}$

$=\frac{1}{(27)^2}(x^{10}y^{14})=\frac{x^{10}y^{14}}{729}$

Thus a. is the right answer.

6 0

3 years ago

Read 2 more answers