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Nikolay [14]
1 year ago
12

What is circumference and pi ?how to solve ?​

Mathematics
1 answer:
alexandr402 [8]1 year ago
3 0

Hi :)

<u>===============================================================</u>

CIRCUMFERENCE

  • The distance all around the circle. Calculated: C=\pi d\qquad or\qquad C=2\pi r.

PI

  • An irrational number. Equals the ratio of a circle's circumference to its diameter. It's approximately 3.

Learn more;work harder

#Carryonlearning

<u>===============================================================</u>

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The difference from home to
Amanda [17]

Answer:

\frac{3}{8}\ mile

Step-by-step explanation:

-Amy walks a distance of 7/8 mile

-Tom walks a distance of 4/8 mile.

#We immediately notice that Amy has walked a longer distance than Tom.

We subtract Tom's distance from Amy's to find how much further Amy walked;

\bigtriangleup d=d_A-d_T\\\\=\frac{7}{8}-\frac{4}{8}\\\\=\frac{3}{8} mile

Hence, Amy has walked 3/8 miles further than Tom has.

6 0
2 years ago
Please help and add steps!!
Veseljchak [2.6K]

Answer:

so what yhu want to do is 9 times 3  than 5y times 37

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
Read 2 more answers
What is the slope-intercept form of the equation -3x + y=12
Musya8 [376]
Answer: y=3x+12

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8 0
2 years ago
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Reagan is using geometry software to construct a regular pentagon by using rotations.
LekaFEV [45]
I would assume that he's using a 90° rotation.
5 0
3 years ago
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