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Nikolay [14]
1 year ago
12

What is circumference and pi ?how to solve ?​

Mathematics
1 answer:
alexandr402 [8]1 year ago
3 0

Hi :)

<u>===============================================================</u>

CIRCUMFERENCE

  • The distance all around the circle. Calculated: C=\pi d\qquad or\qquad C=2\pi r.

PI

  • An irrational number. Equals the ratio of a circle's circumference to its diameter. It's approximately 3.

Learn more;work harder

#Carryonlearning

<u>===============================================================</u>

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Need help! Stuck on this help! help! help
nexus9112 [7]

The amount of fabric in inches Felicia need to make the actual shape for the comforter is 660 in²

<h3>What is a trapezoid?</h3>

It is defined as the quadrilateral having four sides in which two sides are parallel to each other, it is a 2-dimensional geometry.

We have a trapezoid in the picture shown with dimensions.

We know the area of the trapezoid is given by:

\rm A = \dfrac{a+b}{2} \times h

Here a = 15 cm, b = 22 cm and h = 11 cm

\rm A = \dfrac{15+22}{2} \times 11

A = 203.5 square cm

To make the square from the trapezoid, Felicia needs to cut two triangles from the both end, as shown in the figure.

The height of the triangle = 11 cm

And base length = (22-15)/2 = 3.5 cm

The area of the triangle = (11×3.5)/2 = 19.25 square cm

Area of the two triangles = 2×19.25 = 38.5 square cm

Now the amount of fabric  =  203.5 -  38.5 = 165 square cm

As the scale is given 1 cm = 2 in

1 cm ² = 4 in²

So, the amount of fabric in inches = 165×4 = 660 in²

Thus, the amount of fabric in inches Felicia need to make the actual shape for the comforter is 660 in²

Learn more about the trapezoid here:

brainly.com/question/8643562

#SPJ1

3 0
2 years ago
Find the arc length for a circle with diameter 10 inches and central angle 60 degrees. Round to the nearest tenth.
UkoKoshka [18]

Answer:

C. 5.2 cm

Step-by-step explanation:

Arc length formula:

s = \dfrac{n}{360^\circ} 2 \pi r

where s = arc length

n = central angle of arc

r = radius of circle

diamter = d = 10 cm

r = d/2 = 10 cm/2 = 5 cm

n = 60 deg

s = \dfrac{n}{360^\circ} 2 \pi r

s = \dfrac{60^\circ}{360^\circ} 2 \times 3.14159 \times 5 ~cm

s = 5.2~cm

Answer: 5.2 cm

6 0
3 years ago
Make y the subject<br> z+2 = 2/1-y
s344n2d4d5 [400]
Y= subject or y1/2=2
3 0
2 years ago
I have 2 mor quizzes of this assiment day 1 of trying to start 9th grade language arts
Scilla [17]

The change in temperature is -28°F

So, Option D is correct.

Step-by-step explanation:

Temperature at day time = 72°F

Temperature at night = 44°F

What number represents the change in number?

Change in temperature = Temperature at night - Temperature at Day

Change in temperature = 44°F-75°F

Change in temperature = -28°F

The change in temperature is -28°F

So, Option D is correct.

Keywords: Solving Expressions

Learn more about Solving Expressions at:

  • brainly.com/question/9045597
  • brainly.com/question/3739260
  • brainly.com/question/13168205

#learnwithBrainly

3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%5Cleft.%20%5Cbegin%7Bcases%7D%20%7B%208%20x%20%2B%202%20y%20%3D%2046%20%7D%20%5C%5C%20%7B%207
Brut [27]

\huge \boxed{\mathfrak{Question} \downarrow}

\left. \begin{cases} { 8 x + 2 y = 46 } \\ { 7 x + 3 y = 47 } \end{cases} \right.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

\left. \begin{cases} { 8 x + 2 y = 46 } \\ { 7 x + 3 y = 47 } \end{cases} \right.

First, write both the equations in its standard form.

8x+2y=46\\ 7x+3y=47

Now, write the equations in form of matrix.

\left(\begin{matrix}8&2\\7&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}46\\47\end{matrix}\right)

Then, multiply the equation towards the left by using the inverse of matrix \left(\begin{matrix}8&2\\7&3\end{matrix}\right)

\sf \: inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}8&2\\7&3\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)

The product of the matrix & its inverse will be the identity matrix.

\sf\left(\begin{matrix}1&0\\0&1\end{matrix}\right)\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)

Now, multiply the matrices that lie on the left-hand side of the equal sign.

\sf\left(\begin{matrix}x\\y\end{matrix}\right)=inverse(\left(\begin{matrix}8&2\\7&3\end{matrix}\right))\left(\begin{matrix}46\\47\end{matrix}\right)

For the 2 × 2 matrix \left(\begin{matrix}a&b\\c&d\end{matrix}\right), the inverse matrix is ⇨ \left(\begin{matrix}\frac{d}{ad-bc}&\frac{-b}{ad-bc}\\\frac{-c}{ad-bc}&\frac{a}{ad-bc}\end{matrix}\right).

\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{8\times 3-2\times 7}&-\frac{2}{8\times 3-2\times 7}\\-\frac{7}{8\times 3-2\times 7}&\frac{8}{8\times 3-2\times 7}\end{matrix}\right)\left(\begin{matrix}46\\47\end{matrix}\right)

Do the calculations.

\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{10}&-\frac{1}{5}\\-\frac{7}{10}&\frac{4}{5}\end{matrix}\right)\left(\begin{matrix}46\\47\end{matrix}\right)

Multiply the matrices.

\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{3}{10}\times 46-\frac{1}{5}\times 47\\-\frac{7}{10}\times 46+\frac{4}{5}\times 47\end{matrix}\right)

Do the arithmetics again.

\left(\begin{matrix}x\\y\end{matrix}\right)=\left(\begin{matrix}\frac{22}{5}  \\\frac{27}{5}\end{matrix}\right)

Finally, extract the matrix elements x & y & write them separately.

\large \boxed{ \boxed{ \bf \: x=\frac{22}{5},y=\frac{27}{5} }}

3 0
3 years ago
Read 2 more answers
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