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makvit [3.9K]
3 years ago
15

A box contains red marbles and green marbles. Sampling at random from the box five times with replacement, you have drawn a red

marble all five times. What is the probability of drawing a red marble the sixth time
Mathematics
1 answer:
olasank [31]3 years ago
3 0

Answer: The probability of drawing a red marble the sixth time is 1/2

Step-by-step explanation:

Here is the complete question:

A box contains 10 red marbles and 10 green marbles. Sampling at random from the box five times with replacement, you have drawn a red marble all five times. What is the probability of drawing a red marble the sixth time?

Explanation:

Since the sampling at random from the box containing the marbles is with replacement, that is, after picking a marble, it is replaced before picking another one, the probability of picking a red marble is the same for each sampling. Probability, P(A) is given by the ratio of the number of favourable outcome to the total number of favourable outcome.

From the question,

Number of favourable outcome = number of red marbles =10

Total number of favourable outcome = total number of marbles = 10+10= 20

Hence, probability of drawing a red marble P(R) = 10 ÷ 20

P(R) = 1/2

Since the probability of picking a red marble is the same for each sampling, the probability of picking a red marble the sixth time is 1/2

You might be interested in
You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a
Karo-lina-s [1.5K]

Answer:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967      

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

\bar X=573 represent the sample mean

\mu population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

The degrees of freedom are given by:

df=n-1=36-1=35

The Confidence level is 0.90 or 90%, the significance would be \alpha=0.1 and \alpha/2 =0.05, and the critical value for this case would be t_{\alpha/2}=1.690

And replacing we got:

573-1.690\frac{22}{\sqrt{36}}=566.8033    

573+1.690\frac{22}{\sqrt{36}}=579.1967    

And the 90% confidence interval would be between [566.8033 and 579.1967]

6 0
3 years ago
6) The sum of three consecutive numbers is 120.<br> What is the smallest of the three numbers ?
bekas [8.4K]

Answer:

39

Step-by-step explanation:

Let the smallest number be n,

then the three numbers are n, n+1 and n+2

Therefore, n+(n+1)+(n+2)=120

Collecting like terms,

n+n+n=120-1-2

3n=117

n=117/3

n=39

Therefore the numbers are 39,40 and 41.

And the smallest number is 39.

8 0
3 years ago
Which choice is the appropriate simplified form n restriction for the variable 3x^2 + 6x / x^2 - 2x - 8
mrs_skeptik [129]
\frac{3x^{2}+6x}{x^{2}-2x-8} = \frac{3x(x+2)}{(x-4)(x+2)}= \frac{3x}{x-4} &#10;\\ \\ \frac{3x}{x-4} , x \neq 4

x \neq -2
3 0
2 years ago
Harold has 4 classes each morning. Each class is 1 hour long, and there are 10 minutes between classes. The first class is at 8
Viktor [21]

The fourth class ends at 12:30 pm

<em><u>Solution:</u></em>

Given that Harold has 4 classes each morning

Each class is 1 hour long, and there are 10 minutes between classes

The first class is at 8 A.M

<em><u>To find: Time at which fourth class ends</u></em>

Since each is 1 hour long and 10 minutes gap between classes

First class = 8 A.M to 9 A.M

Second class = 9:10 A.M to 10 : 10 AM

Third class = 10 : 20 AM to 11 : 20 AM

Fourth class = 11 : 30 AM to 12 : 30 PM

Thus the fourth class ends at 12:30 pm

4 0
2 years ago
PLZ
g100num [7]

Answer:

21 pairs of socks

Step-by-step explanation:

We can find out how much money Chang has to spend on socks by subtracting the price of sneakers from his total money to spend by solving 160 - 95. From that, we get our answer of $65 that Chang has to spend on socks. We can divide 65 by 3 to see how many pairs of socks he can buy and we get our answer of 21 pairs of socks.

(sorry if it's confusing but I hope it helped anyway)

8 0
2 years ago
Read 2 more answers
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