Arrange your given equation to resembles the form
a^2 +2ab+ b^2 because this equals (a+b)^2
So we get:
y^2+16y+8^2=0
Now compare
y^2+16y+8^2 to a^2 +2ab+ b^2
So we got
y^2+2•8 y+8^2=0 which equals (y+8)^2
We analyze the chart and observe that the linear function is

, since this relation holds for all values in the table. Drawing this line over the quadratic function shows that they intersect
twice, at
both the positive and negative x-coordinates.This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on! To prove this more rigorously, we can find that the equation of the parabola is
Substituting in

, we find that
the intersection points occur where 
, or

or

This equation doesn't factor nicely, so we use the
quadratic formula to learn that

Hence, the x-coordinates of the intersection points are

, which is
positive, and

, which is
negative. This proves that there are intersection points on both ends of the axis.
Step-by-step explanation:
in moving from the point let say A(7,0) to the point B(-1,3), the x-coordinate increases by (7-(-1)= 8 while the y-coordinate decreses by (0-3)=-3. The same of this is given by finding the square of 8=64 and (-3)=9. by summing the two we have 64+9=73. so we find the square root of 73 which which is 8.55. so therefore the answer is 8.55 which is approximately 9
Just make m the subject m=fa