20 Points + Brainliest for the best answer.

For each correlation coefficient below, calculate what proportion of variance is shared by the two correlated variables:

Viefleur [7K]

Answer:

A. 0.0625

B. 0.1089

C. 0.81

D. 0.0196

Step-by-step explanation:

The proportion of variance is shared by the two correlated variables is given as the r².

Therefore,

For A. r = 0.25

Proportion of variance is shared by the two correlated variables = 0.25²

= 0.0625

For B. r = 0.33

Proportion of variance is shared by the two correlated variables = 0.33²

= 0.1089

For C. r = 0.90

Proportion of variance is shared by the two correlated variables = 0.90²

= 0.81

For D. r = 0.14

Proportion of variance is shared by the two correlated variables = 0.14²

= 0.0196

4 0

3 years ago

Find the missing side lengths.<br><br> Can someone please help???

adoni [48]

Answer:

x = 16

y = 13.8

Step-by-step explanation:

6 0

3 years ago

Hannah scored 14/18 on her math test and trey scored 16/20 his math test.Who did the best?

tia_tia [17]

Compare
first simplify each
14/18=2/2 times 7/9=1 times 7/9=7/9

16/20=2/2 times 2/2 times 4/5=1 times 4/5=4/5

7/9 and 4/5
make bottom number same
7/9 times 5/5=35/45
4/5 times 9/9=36/45
36/45>35/45

trey scored better

3 0

4 years ago

Read 2 more answers

g A programmer plans to develop a new software system. In planning for the operating system that he will use, he needs to estim

kipiarov [429]

Answer:

a) n= 1045 computers

b) n= 442 computers

c) A. Yes, using the additional survey information from part (b) dramatically reduces the sample size.

Step-by-step explanation:

Hello!

The variable of interest is

X: Number of computers that use the new operating system.

You need to find the best sample size to take so that the proportion of computers that use the new operating system can be estimated with a 99% CI and a margin of error no greater than 4%.

The confidence interval for the population proportion is:

p' ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$Z_{1-\alpha /2}= Z_{0.995}= 2.586$

a) In this item there is no known value for the sample proportion (p') when something like this happens, you have to assume the "worst-case scenario" that is, that the proportion of success and failure of the trial are the same, i.e. p'=q'=0.5

The margin of error of the interval is:

d= $Z_{1-\alpha /2}$ * $\sqrt{\frac{p'(1-p')}{n} }$

$\frac{d}{Z_{1-\alpha /2}} = \sqrt{\frac{p'(1-p)}{n} }$

$(\frac{d}{Z_{1-\alpha /2}})^2 = \frac{p'(1-p')}{n}$

$n * (\frac{d}{Z_{1-\alpha /2}})^2 = p'(1-p')$

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n=[0.5(1-0.5)]*(\frac{2.586}{0.04} )^2= 1044.9056$

n= 1045 computers

b) This time there is a known value for the sample proportion: p'= 0.88, using the same confidence level and required margin of error:

$n= [p'(1-p')]*(\frac{Z_{1-\alpha /2}}{d} )^2$

$n= [0.88*0.12]*(\frac{{2.586}}{0.04})^2= 441.3681$

n= 442 computers

c) The additional information in part b affected the required sample size, it was drastically decreased in comparison with the sample size calculated in a).

I hope it helps!

4 0

4 years ago

Solve for X. Need help with this simple maths question as soon as possible. Thanks. Question attached

elixir [45]

Answer:

2(x-√a)² + x - √a +1

Step-by-step explanation:

use x-√a as value for x

f(x-√a) = 2(x-√a)² + x - √a +1

7 0

3 years ago