Question

Density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubic meters.

Answer 1

Answer:

$5.23 * 10^{3} \frac{kg}{m^3}$.

Step-by-step explanation:

$5.23 * 10^{-6} \frac{kg}{mm^3}$. We have that $1m^3 = 10^9 mm^3$. Now,

$5.23 * 10^{-6} \frac{kg}{mm^3} \frac{10^9 mm^3}{1m^3}$

$5.23 * 10^{-6}*10^9 \frac{kg}{m^3} = 5.23 * 10^{3} \frac{kg}{m^3}$.

Answer 2

 In a laboratory, you determine that the density of a certain solid is 5.23×10−6kg/mm3. Convert this density into kilograms per cubic meter. 
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5.23×10^−6 kg/mm3 x 1000 mm^3/cm^3 x 1000 cm^3/dm^3 

x 1000 dm^3/m^3 = 5230 kg/m^3. 

notice how all the units cancel out but the required.